How to check if all elements of 1 list are in the *same quantity* and in any order, in the list2? The Next CEO of Stack OverflowChecking if list is a sublistHow do I check if a list is empty?How to generate all permutations of a list in PythonHow do you remove duplicates from a list whilst preserving order?How do I remove an element from a list by index in Python?How do I get the number of elements in a list in Python?How do I list all files of a directory?check if all elements in a list are identicalHow to check if all items in a list are there in another list?Checking for sublists in list of lists preserving sequencePrint 'x' amount of items 'y' times?

Is it possible to use a NPN BJT as switch, from single power source?

"misplaced omit" error when >centering columns

Why the difference in type-inference over the as-pattern in two similar function definitions?

Is it convenient to ask the journal's editor for two additional days to complete a review?

What is the value of α and β in a triangle?

Does Germany produce more waste than the US?

When you upcast Blindness/Deafness, do all targets suffer the same effect?

Math-accent symbol over parentheses enclosing accented symbol (amsmath)

Why does standard notation not preserve intervals (visually)

Solving system of ODEs with extra parameter

Does increasing your ability score affect your main stat?

Chain wire methods together in Lightning Web Components

Why, when going from special to general relativity, do we just replace partial derivatives with covariant derivatives?

I want to delete every two lines after 3rd lines in file contain very large number of lines :

Missile strike detection (but it's not actually a missile)

Domestic-to-international connection at Orlando (MCO)

Is there a way to save my career from absolute disaster?

The past simple of "gaslight" – "gaslighted" or "gaslit"?

How to place nodes around a circle from some initial angle?

Can MTA send mail via a relay without being told so?

Is there always a complete, orthogonal set of unitary matrices?

Writing differences on a blackboard

Why isn't acceleration always zero whenever velocity is zero, such as the moment a ball bounces off a wall?

Why do remote US companies require working in the US?



How to check if all elements of 1 list are in the *same quantity* and in any order, in the list2?



The Next CEO of Stack OverflowChecking if list is a sublistHow do I check if a list is empty?How to generate all permutations of a list in PythonHow do you remove duplicates from a list whilst preserving order?How do I remove an element from a list by index in Python?How do I get the number of elements in a list in Python?How do I list all files of a directory?check if all elements in a list are identicalHow to check if all items in a list are there in another list?Checking for sublists in list of lists preserving sequencePrint 'x' amount of items 'y' times?










7















I know its a very common question at first, but I haven't found one that specific. (If you do, please tell me.) And all ways I found didnt work for me.
I need to check if all elements of list 1 appears in the same amount in the list2.



Ex :



#If list1 = [2,2,2,6] 
# and list2 =[2,6,2,5,2,4]
#then all list1 are in list2.
#If list2 = [2,6] then all list1 are not in list2.


i'm trying this way :



list1 = [6,2]

import itertools

for i in itertools.product((2,4,5,1), repeat=3) :
asd = i[0] + i[1]
asd2= i[1] + i[2]

list2 = [asd, asd2]
if all(elem in list2 for elem in list1):
print (i,list2)


It works when the elements are not repeated in the list1, like [1,2]. But when they are repeated, all repeated elements is beeing counted as only 1 : [2,2,2] its beeing understanded as [2]. Or so i think.










share|improve this question



















  • 1





    After reading both questions, it does not look like a duplicate to me. This question cares about quantity, but not order. The other one cares about order, but not quantity.

    – gilch
    5 hours ago















7















I know its a very common question at first, but I haven't found one that specific. (If you do, please tell me.) And all ways I found didnt work for me.
I need to check if all elements of list 1 appears in the same amount in the list2.



Ex :



#If list1 = [2,2,2,6] 
# and list2 =[2,6,2,5,2,4]
#then all list1 are in list2.
#If list2 = [2,6] then all list1 are not in list2.


i'm trying this way :



list1 = [6,2]

import itertools

for i in itertools.product((2,4,5,1), repeat=3) :
asd = i[0] + i[1]
asd2= i[1] + i[2]

list2 = [asd, asd2]
if all(elem in list2 for elem in list1):
print (i,list2)


It works when the elements are not repeated in the list1, like [1,2]. But when they are repeated, all repeated elements is beeing counted as only 1 : [2,2,2] its beeing understanded as [2]. Or so i think.










share|improve this question



















  • 1





    After reading both questions, it does not look like a duplicate to me. This question cares about quantity, but not order. The other one cares about order, but not quantity.

    – gilch
    5 hours ago













7












7








7








I know its a very common question at first, but I haven't found one that specific. (If you do, please tell me.) And all ways I found didnt work for me.
I need to check if all elements of list 1 appears in the same amount in the list2.



Ex :



#If list1 = [2,2,2,6] 
# and list2 =[2,6,2,5,2,4]
#then all list1 are in list2.
#If list2 = [2,6] then all list1 are not in list2.


i'm trying this way :



list1 = [6,2]

import itertools

for i in itertools.product((2,4,5,1), repeat=3) :
asd = i[0] + i[1]
asd2= i[1] + i[2]

list2 = [asd, asd2]
if all(elem in list2 for elem in list1):
print (i,list2)


It works when the elements are not repeated in the list1, like [1,2]. But when they are repeated, all repeated elements is beeing counted as only 1 : [2,2,2] its beeing understanded as [2]. Or so i think.










share|improve this question
















I know its a very common question at first, but I haven't found one that specific. (If you do, please tell me.) And all ways I found didnt work for me.
I need to check if all elements of list 1 appears in the same amount in the list2.



Ex :



#If list1 = [2,2,2,6] 
# and list2 =[2,6,2,5,2,4]
#then all list1 are in list2.
#If list2 = [2,6] then all list1 are not in list2.


i'm trying this way :



list1 = [6,2]

import itertools

for i in itertools.product((2,4,5,1), repeat=3) :
asd = i[0] + i[1]
asd2= i[1] + i[2]

list2 = [asd, asd2]
if all(elem in list2 for elem in list1):
print (i,list2)


It works when the elements are not repeated in the list1, like [1,2]. But when they are repeated, all repeated elements is beeing counted as only 1 : [2,2,2] its beeing understanded as [2]. Or so i think.







python python-3.x






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited 5 hours ago









petezurich

3,76581936




3,76581936










asked 6 hours ago









Vitor OliveiraVitor Oliveira

525




525







  • 1





    After reading both questions, it does not look like a duplicate to me. This question cares about quantity, but not order. The other one cares about order, but not quantity.

    – gilch
    5 hours ago












  • 1





    After reading both questions, it does not look like a duplicate to me. This question cares about quantity, but not order. The other one cares about order, but not quantity.

    – gilch
    5 hours ago







1




1





After reading both questions, it does not look like a duplicate to me. This question cares about quantity, but not order. The other one cares about order, but not quantity.

– gilch
5 hours ago





After reading both questions, it does not look like a duplicate to me. This question cares about quantity, but not order. The other one cares about order, but not quantity.

– gilch
5 hours ago












2 Answers
2






active

oldest

votes


















8














Use collections.Counter to convert to a dict_items view Set of (value, count) pairs. Then you can use normal set operations.



from collections import Counter

def a_all_in_b(a, b):
"""True only if all elements of `a` are in `b` in the *same quantity* (in any order)."""
return Counter(a).items() <= Counter(b).items()


Note that Counter only works on hashable elements because it's a subclass of dict.






share|improve this answer




















  • 1





    that's slick @gilch

    – modesitt
    5 hours ago











  • Does this work for something like a_all_in_b([1], [1, 1])?

    – Tomothy32
    5 hours ago











  • @Tomothy32 It should return False in that case, because the 1's are not "in the same quantity".

    – gilch
    5 hours ago












  • @gilch The question is a bit fuzzy regarding this, but I have to admit that you probably interpreted it correctly.

    – Tomothy32
    5 hours ago






  • 1





    Also it should be <=, not <.

    – user2357112
    5 hours ago


















1














Modify this answer to Checking if list is a sublist to check for equality of occurences:



from collections import Counter 

list1 = [2,2,2,6]
list2 =[2,6,2,5,2,4]

def same_amount(a,b):
c1 = Counter(a)
c2 = Counter(b)

for key,value in c1.items():
if c2[key] != value:
return False
return True


print(same_amount(list1,list2))
print(same_amount(list1 + [2],list2))


Output:



True
False


There is almost no transfere-knowledge needed to create this answer, thats why I suggested it as dupe. This question is simply a more specific case of what Checking if list is a sublist discussed.






share|improve this answer























  • It works too. Thanks !

    – Vitor Oliveira
    4 hours ago











Your Answer






StackExchange.ifUsing("editor", function ()
StackExchange.using("externalEditor", function ()
StackExchange.using("snippets", function ()
StackExchange.snippets.init();
);
);
, "code-snippets");

StackExchange.ready(function()
var channelOptions =
tags: "".split(" "),
id: "1"
;
initTagRenderer("".split(" "), "".split(" "), channelOptions);

StackExchange.using("externalEditor", function()
// Have to fire editor after snippets, if snippets enabled
if (StackExchange.settings.snippets.snippetsEnabled)
StackExchange.using("snippets", function()
createEditor();
);

else
createEditor();

);

function createEditor()
StackExchange.prepareEditor(
heartbeatType: 'answer',
autoActivateHeartbeat: false,
convertImagesToLinks: true,
noModals: true,
showLowRepImageUploadWarning: true,
reputationToPostImages: 10,
bindNavPrevention: true,
postfix: "",
imageUploader:
brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
allowUrls: true
,
onDemand: true,
discardSelector: ".discard-answer"
,immediatelyShowMarkdownHelp:true
);



);













draft saved

draft discarded


















StackExchange.ready(
function ()
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fstackoverflow.com%2fquestions%2f55435166%2fhow-to-check-if-all-elements-of-1-list-are-in-the-same-quantity-and-in-any-ord%23new-answer', 'question_page');

);

Post as a guest















Required, but never shown

























2 Answers
2






active

oldest

votes








2 Answers
2






active

oldest

votes









active

oldest

votes






active

oldest

votes









8














Use collections.Counter to convert to a dict_items view Set of (value, count) pairs. Then you can use normal set operations.



from collections import Counter

def a_all_in_b(a, b):
"""True only if all elements of `a` are in `b` in the *same quantity* (in any order)."""
return Counter(a).items() <= Counter(b).items()


Note that Counter only works on hashable elements because it's a subclass of dict.






share|improve this answer




















  • 1





    that's slick @gilch

    – modesitt
    5 hours ago











  • Does this work for something like a_all_in_b([1], [1, 1])?

    – Tomothy32
    5 hours ago











  • @Tomothy32 It should return False in that case, because the 1's are not "in the same quantity".

    – gilch
    5 hours ago












  • @gilch The question is a bit fuzzy regarding this, but I have to admit that you probably interpreted it correctly.

    – Tomothy32
    5 hours ago






  • 1





    Also it should be <=, not <.

    – user2357112
    5 hours ago















8














Use collections.Counter to convert to a dict_items view Set of (value, count) pairs. Then you can use normal set operations.



from collections import Counter

def a_all_in_b(a, b):
"""True only if all elements of `a` are in `b` in the *same quantity* (in any order)."""
return Counter(a).items() <= Counter(b).items()


Note that Counter only works on hashable elements because it's a subclass of dict.






share|improve this answer




















  • 1





    that's slick @gilch

    – modesitt
    5 hours ago











  • Does this work for something like a_all_in_b([1], [1, 1])?

    – Tomothy32
    5 hours ago











  • @Tomothy32 It should return False in that case, because the 1's are not "in the same quantity".

    – gilch
    5 hours ago












  • @gilch The question is a bit fuzzy regarding this, but I have to admit that you probably interpreted it correctly.

    – Tomothy32
    5 hours ago






  • 1





    Also it should be <=, not <.

    – user2357112
    5 hours ago













8












8








8







Use collections.Counter to convert to a dict_items view Set of (value, count) pairs. Then you can use normal set operations.



from collections import Counter

def a_all_in_b(a, b):
"""True only if all elements of `a` are in `b` in the *same quantity* (in any order)."""
return Counter(a).items() <= Counter(b).items()


Note that Counter only works on hashable elements because it's a subclass of dict.






share|improve this answer















Use collections.Counter to convert to a dict_items view Set of (value, count) pairs. Then you can use normal set operations.



from collections import Counter

def a_all_in_b(a, b):
"""True only if all elements of `a` are in `b` in the *same quantity* (in any order)."""
return Counter(a).items() <= Counter(b).items()


Note that Counter only works on hashable elements because it's a subclass of dict.







share|improve this answer














share|improve this answer



share|improve this answer








edited 4 hours ago

























answered 5 hours ago









gilchgilch

4,3201716




4,3201716







  • 1





    that's slick @gilch

    – modesitt
    5 hours ago











  • Does this work for something like a_all_in_b([1], [1, 1])?

    – Tomothy32
    5 hours ago











  • @Tomothy32 It should return False in that case, because the 1's are not "in the same quantity".

    – gilch
    5 hours ago












  • @gilch The question is a bit fuzzy regarding this, but I have to admit that you probably interpreted it correctly.

    – Tomothy32
    5 hours ago






  • 1





    Also it should be <=, not <.

    – user2357112
    5 hours ago












  • 1





    that's slick @gilch

    – modesitt
    5 hours ago











  • Does this work for something like a_all_in_b([1], [1, 1])?

    – Tomothy32
    5 hours ago











  • @Tomothy32 It should return False in that case, because the 1's are not "in the same quantity".

    – gilch
    5 hours ago












  • @gilch The question is a bit fuzzy regarding this, but I have to admit that you probably interpreted it correctly.

    – Tomothy32
    5 hours ago






  • 1





    Also it should be <=, not <.

    – user2357112
    5 hours ago







1




1





that's slick @gilch

– modesitt
5 hours ago





that's slick @gilch

– modesitt
5 hours ago













Does this work for something like a_all_in_b([1], [1, 1])?

– Tomothy32
5 hours ago





Does this work for something like a_all_in_b([1], [1, 1])?

– Tomothy32
5 hours ago













@Tomothy32 It should return False in that case, because the 1's are not "in the same quantity".

– gilch
5 hours ago






@Tomothy32 It should return False in that case, because the 1's are not "in the same quantity".

– gilch
5 hours ago














@gilch The question is a bit fuzzy regarding this, but I have to admit that you probably interpreted it correctly.

– Tomothy32
5 hours ago





@gilch The question is a bit fuzzy regarding this, but I have to admit that you probably interpreted it correctly.

– Tomothy32
5 hours ago




1




1





Also it should be <=, not <.

– user2357112
5 hours ago





Also it should be <=, not <.

– user2357112
5 hours ago













1














Modify this answer to Checking if list is a sublist to check for equality of occurences:



from collections import Counter 

list1 = [2,2,2,6]
list2 =[2,6,2,5,2,4]

def same_amount(a,b):
c1 = Counter(a)
c2 = Counter(b)

for key,value in c1.items():
if c2[key] != value:
return False
return True


print(same_amount(list1,list2))
print(same_amount(list1 + [2],list2))


Output:



True
False


There is almost no transfere-knowledge needed to create this answer, thats why I suggested it as dupe. This question is simply a more specific case of what Checking if list is a sublist discussed.






share|improve this answer























  • It works too. Thanks !

    – Vitor Oliveira
    4 hours ago















1














Modify this answer to Checking if list is a sublist to check for equality of occurences:



from collections import Counter 

list1 = [2,2,2,6]
list2 =[2,6,2,5,2,4]

def same_amount(a,b):
c1 = Counter(a)
c2 = Counter(b)

for key,value in c1.items():
if c2[key] != value:
return False
return True


print(same_amount(list1,list2))
print(same_amount(list1 + [2],list2))


Output:



True
False


There is almost no transfere-knowledge needed to create this answer, thats why I suggested it as dupe. This question is simply a more specific case of what Checking if list is a sublist discussed.






share|improve this answer























  • It works too. Thanks !

    – Vitor Oliveira
    4 hours ago













1












1








1







Modify this answer to Checking if list is a sublist to check for equality of occurences:



from collections import Counter 

list1 = [2,2,2,6]
list2 =[2,6,2,5,2,4]

def same_amount(a,b):
c1 = Counter(a)
c2 = Counter(b)

for key,value in c1.items():
if c2[key] != value:
return False
return True


print(same_amount(list1,list2))
print(same_amount(list1 + [2],list2))


Output:



True
False


There is almost no transfere-knowledge needed to create this answer, thats why I suggested it as dupe. This question is simply a more specific case of what Checking if list is a sublist discussed.






share|improve this answer













Modify this answer to Checking if list is a sublist to check for equality of occurences:



from collections import Counter 

list1 = [2,2,2,6]
list2 =[2,6,2,5,2,4]

def same_amount(a,b):
c1 = Counter(a)
c2 = Counter(b)

for key,value in c1.items():
if c2[key] != value:
return False
return True


print(same_amount(list1,list2))
print(same_amount(list1 + [2],list2))


Output:



True
False


There is almost no transfere-knowledge needed to create this answer, thats why I suggested it as dupe. This question is simply a more specific case of what Checking if list is a sublist discussed.







share|improve this answer












share|improve this answer



share|improve this answer










answered 5 hours ago









Patrick ArtnerPatrick Artner

26k62544




26k62544












  • It works too. Thanks !

    – Vitor Oliveira
    4 hours ago

















  • It works too. Thanks !

    – Vitor Oliveira
    4 hours ago
















It works too. Thanks !

– Vitor Oliveira
4 hours ago





It works too. Thanks !

– Vitor Oliveira
4 hours ago

















draft saved

draft discarded
















































Thanks for contributing an answer to Stack Overflow!


  • Please be sure to answer the question. Provide details and share your research!

But avoid


  • Asking for help, clarification, or responding to other answers.

  • Making statements based on opinion; back them up with references or personal experience.

To learn more, see our tips on writing great answers.




draft saved


draft discarded














StackExchange.ready(
function ()
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fstackoverflow.com%2fquestions%2f55435166%2fhow-to-check-if-all-elements-of-1-list-are-in-the-same-quantity-and-in-any-ord%23new-answer', 'question_page');

);

Post as a guest















Required, but never shown





















































Required, but never shown














Required, but never shown












Required, but never shown







Required, but never shown

































Required, but never shown














Required, but never shown












Required, but never shown







Required, but never shown







Popular posts from this blog

How should I use the fbox command correctly to avoid producing a Bad Box message?How to put a long piece of text in a box?How to specify height and width of fboxIs there an arrayrulecolor-like command to change the rule color of fbox?What is the command to highlight bad boxes in pdf?Why does fbox sometimes place the box *over* the graphic image?how to put the text in the boxHow to create command for a box where text inside the box can automatically adjust?how can I make an fbox like command with certain color, shape and width of border?how to use fbox in align modeFbox increase the spacing between the box and it content (inner margin)how to change the box height of an equationWhat is the use of the hbox in a newcommand command?

Doxepinum Nexus interni Notae | Tabula navigationis3158DB01142WHOa682390"Structural Analysis of the Histamine H1 Receptor""Transdermal and Topical Drug Administration in the Treatment of Pain""Antidepressants as antipruritic agents: A review"

inputenc: Unicode character … not set up for use with LaTeX The Next CEO of Stack OverflowEntering Unicode characters in LaTeXHow to solve the `Package inputenc Error: Unicode char not set up for use with LaTeX` problem?solve “Unicode char is not set up for use with LaTeX” without special handling of every new interesting UTF-8 characterPackage inputenc Error: Unicode character ² (U+B2)(inputenc) not set up for use with LaTeX. acroI2C[I²C]package inputenc error unicode char (u + 190) not set up for use with latexPackage inputenc Error: Unicode char u8:′ not set up for use with LaTeX. 3′inputenc Error: Unicode char u8: not set up for use with LaTeX with G-BriefPackage Inputenc Error: Unicode char u8: not set up for use with LaTeXPackage inputenc Error: Unicode char ́ (U+301)(inputenc) not set up for use with LaTeX. includePackage inputenc Error: Unicode char ̂ (U+302)(inputenc) not set up for use with LaTeX. … $widehatleft (OA,AA' right )$Package inputenc Error: Unicode char â„¡ (U+2121)(inputenc) not set up for use with LaTeX. printbibliography[heading=bibintoc]Package inputenc Error: Unicode char − (U+2212)(inputenc) not set up for use with LaTeXPackage inputenc Error: Unicode character α (U+3B1) not set up for use with LaTeXPackage inputenc Error: Unicode characterError: ! Package inputenc Error: Unicode char ⊘ (U+2298)(inputenc) not set up for use with LaTeX