Plot of a tornado shape like surfaceDrawing a shape on the mesh of a Plot3DHow to make a smooth revolution surface plotPlotting 3D arrows on a surfaceSurface Plot 3D of a strongly concave shapePlot closed surface with ListPlot3DA method to draw a surface around a set of regularly spaced pointsPlot a revolution surface, with two cross sections to show its shapeHow to draw a proper surface with ListPlot3D?How to convert a polar plot in surface PlotPlot surface defined by inequality
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Plot of a tornado shape like surface
Drawing a shape on the mesh of a Plot3DHow to make a smooth revolution surface plotPlotting 3D arrows on a surfaceSurface Plot 3D of a strongly concave shapePlot closed surface with ListPlot3DA method to draw a surface around a set of regularly spaced pointsPlot a revolution surface, with two cross sections to show its shapeHow to draw a proper surface with ListPlot3D?How to convert a polar plot in surface PlotPlot surface defined by inequality
$begingroup$
Which will be a simple code to plot a shape of a surface tornado like cone?
Any help is welcome.
plotting
asked 4 hours ago
janmarqzjanmarqz
1163
New contributor
janmarqz is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
$endgroup$
add a comment |
$begingroup$
Which will be a simple code to plot a shape of a surface tornado like cone?
Any help is welcome.
plotting
asked 4 hours ago
janmarqzjanmarqz
1163
New contributor
janmarqz is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
$endgroup$
add a comment |
$begingroup$
Which will be a simple code to plot a shape of a surface tornado like cone?
Any help is welcome.
plotting
asked 4 hours ago
janmarqzjanmarqz
1163
New contributor
janmarqz is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
$endgroup$
Which will be a simple code to plot a shape of a surface tornado like cone?
Any help is welcome.
plotting
plotting
asked 4 hours ago
janmarqzjanmarqz
1163
New contributor
janmarqz is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
asked 4 hours ago
janmarqzjanmarqz
1163
New contributor
janmarqz is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
asked 4 hours ago
janmarqzjanmarqz
1163
New contributor
janmarqz is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
asked 4 hours ago
janmarqzjanmarqz
1163
asked 4 hours ago
janmarqzjanmarqz
1163
1163
New contributor
janmarqz is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
New contributor
janmarqz is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
janmarqz is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
add a comment |
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2 Answers
2
active
oldest
votes
$begingroup$
My quick go at it:
ContourPlot3D[
(x - z/5 Cos[[Pi] z])^2 + (y - z/5 Sin[[Pi] z])^2 == (z/4)^2
, x, -1, 1, y, -1, 1, z, 0, 2
, Mesh -> None, Axes -> False, Boxed -> False
, PlotTheme -> "ThickSurface", ContourStyle -> RGBColor[0.41, 0.5, 0.63]
]
answered 3 hours ago
Thies HeideckeThies Heidecke
7,0712638
$endgroup$
add a comment |
$begingroup$
I like "surface synthesis" questions. Here's a simple-minded model that combines an Archimedean spiral with a power law curve:
With[h = 1/10, n = 24, c = 4, p = 2/3,
ParametricPlot3D[t (h Cos[n t] + Cos[v]), t (h Sin[n t] + Sin[v]), (c t)^p,
t, 0, 3, v, 0, 2 π, Axes -> None, Boxed -> False,
Lighting -> "Neutral", Mesh -> False, PlotPoints -> 85,
PlotStyle -> Opacity[3/4, Black], ViewPoint -> 3.2, -1.6, 1.]]
Adjust parameters as seen fit.
answered 38 mins ago
J. M. is slightly pensive♦J. M. is slightly pensive
98.1k10306465
$endgroup$
add a comment |
Your Answer
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2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
$begingroup$
My quick go at it:
ContourPlot3D[
(x - z/5 Cos[[Pi] z])^2 + (y - z/5 Sin[[Pi] z])^2 == (z/4)^2
, x, -1, 1, y, -1, 1, z, 0, 2
, Mesh -> None, Axes -> False, Boxed -> False
, PlotTheme -> "ThickSurface", ContourStyle -> RGBColor[0.41, 0.5, 0.63]
]
answered 3 hours ago
Thies HeideckeThies Heidecke
7,0712638
$endgroup$
add a comment |
$begingroup$
My quick go at it:
ContourPlot3D[
(x - z/5 Cos[[Pi] z])^2 + (y - z/5 Sin[[Pi] z])^2 == (z/4)^2
, x, -1, 1, y, -1, 1, z, 0, 2
, Mesh -> None, Axes -> False, Boxed -> False
, PlotTheme -> "ThickSurface", ContourStyle -> RGBColor[0.41, 0.5, 0.63]
]
answered 3 hours ago
Thies HeideckeThies Heidecke
7,0712638
$endgroup$
add a comment |
$begingroup$
My quick go at it:
ContourPlot3D[
(x - z/5 Cos[[Pi] z])^2 + (y - z/5 Sin[[Pi] z])^2 == (z/4)^2
, x, -1, 1, y, -1, 1, z, 0, 2
, Mesh -> None, Axes -> False, Boxed -> False
, PlotTheme -> "ThickSurface", ContourStyle -> RGBColor[0.41, 0.5, 0.63]
]
answered 3 hours ago
Thies HeideckeThies Heidecke
7,0712638
$endgroup$
My quick go at it:
ContourPlot3D[
(x - z/5 Cos[[Pi] z])^2 + (y - z/5 Sin[[Pi] z])^2 == (z/4)^2
, x, -1, 1, y, -1, 1, z, 0, 2
, Mesh -> None, Axes -> False, Boxed -> False
, PlotTheme -> "ThickSurface", ContourStyle -> RGBColor[0.41, 0.5, 0.63]
]
answered 3 hours ago
Thies HeideckeThies Heidecke
7,0712638
answered 3 hours ago
Thies HeideckeThies Heidecke
7,0712638
answered 3 hours ago
Thies HeideckeThies Heidecke
7,0712638
answered 3 hours ago
Thies HeideckeThies Heidecke
7,0712638
7,0712638
add a comment |
add a comment |
$begingroup$
I like "surface synthesis" questions. Here's a simple-minded model that combines an Archimedean spiral with a power law curve:
With[h = 1/10, n = 24, c = 4, p = 2/3,
ParametricPlot3D[t (h Cos[n t] + Cos[v]), t (h Sin[n t] + Sin[v]), (c t)^p,
t, 0, 3, v, 0, 2 π, Axes -> None, Boxed -> False,
Lighting -> "Neutral", Mesh -> False, PlotPoints -> 85,
PlotStyle -> Opacity[3/4, Black], ViewPoint -> 3.2, -1.6, 1.]]
Adjust parameters as seen fit.
answered 38 mins ago
J. M. is slightly pensive♦J. M. is slightly pensive
98.1k10306465
$endgroup$
add a comment |
$begingroup$
I like "surface synthesis" questions. Here's a simple-minded model that combines an Archimedean spiral with a power law curve:
With[h = 1/10, n = 24, c = 4, p = 2/3,
ParametricPlot3D[t (h Cos[n t] + Cos[v]), t (h Sin[n t] + Sin[v]), (c t)^p,
t, 0, 3, v, 0, 2 π, Axes -> None, Boxed -> False,
Lighting -> "Neutral", Mesh -> False, PlotPoints -> 85,
PlotStyle -> Opacity[3/4, Black], ViewPoint -> 3.2, -1.6, 1.]]
Adjust parameters as seen fit.
answered 38 mins ago
J. M. is slightly pensive♦J. M. is slightly pensive
98.1k10306465
$endgroup$
add a comment |
$begingroup$
I like "surface synthesis" questions. Here's a simple-minded model that combines an Archimedean spiral with a power law curve:
With[h = 1/10, n = 24, c = 4, p = 2/3,
ParametricPlot3D[t (h Cos[n t] + Cos[v]), t (h Sin[n t] + Sin[v]), (c t)^p,
t, 0, 3, v, 0, 2 π, Axes -> None, Boxed -> False,
Lighting -> "Neutral", Mesh -> False, PlotPoints -> 85,
PlotStyle -> Opacity[3/4, Black], ViewPoint -> 3.2, -1.6, 1.]]
Adjust parameters as seen fit.
answered 38 mins ago
J. M. is slightly pensive♦J. M. is slightly pensive
98.1k10306465
$endgroup$
I like "surface synthesis" questions. Here's a simple-minded model that combines an Archimedean spiral with a power law curve:
With[h = 1/10, n = 24, c = 4, p = 2/3,
ParametricPlot3D[t (h Cos[n t] + Cos[v]), t (h Sin[n t] + Sin[v]), (c t)^p,
t, 0, 3, v, 0, 2 π, Axes -> None, Boxed -> False,
Lighting -> "Neutral", Mesh -> False, PlotPoints -> 85,
PlotStyle -> Opacity[3/4, Black], ViewPoint -> 3.2, -1.6, 1.]]
Adjust parameters as seen fit.
answered 38 mins ago
J. M. is slightly pensive♦J. M. is slightly pensive
98.1k10306465
answered 38 mins ago
J. M. is slightly pensive♦J. M. is slightly pensive
98.1k10306465
answered 38 mins ago
J. M. is slightly pensive♦J. M. is slightly pensive
98.1k10306465
answered 38 mins ago
J. M. is slightly pensive♦J. M. is slightly pensive
98.1k10306465
98.1k10306465
add a comment |
add a comment |
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