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Escape a backup date in a file name


Converting a string from a file into a dateHow to append date to backup fileCreate sub-directories and organize files by date from file namecannot create regular file 'filename': File existsHow to append a date to all files in a directory without touching sub-directories via bash scriptadding date to beginning of file name using scriptinserting modified date into filename - 2 casesCan the date command take as argument a date string in a file given by another date command?Set file modification date from date stored as filenameHow to Find and delete File Older than 3 years without scaning on modified date?













3















I have been trying to:



cp file.csv file.$(date +%D).csv


But it fails because the filenames is: file.03/27/19.csv with the slash of separate directories.



And I have been trying again to:



cp file.csv file.$(printf "%q" $(date +%D)).csv


But it still fails.










share|improve this question
























  • You can not set a filename with slash characters: stackoverflow.com/questions/9847288/…

    – tres.14159
    5 hours ago











  • the problem is your use of the date format using the / character. You said it yourself, the shell is seeing them as directory markers. Try one of the many other options available from date. You might be able to get the / escaped so the filename uses the character code (like putting a space in a filename), but that is often problematic.

    – 0xSheepdog
    5 hours ago
















3















I have been trying to:



cp file.csv file.$(date +%D).csv


But it fails because the filenames is: file.03/27/19.csv with the slash of separate directories.



And I have been trying again to:



cp file.csv file.$(printf "%q" $(date +%D)).csv


But it still fails.










share|improve this question
























  • You can not set a filename with slash characters: stackoverflow.com/questions/9847288/…

    – tres.14159
    5 hours ago











  • the problem is your use of the date format using the / character. You said it yourself, the shell is seeing them as directory markers. Try one of the many other options available from date. You might be able to get the / escaped so the filename uses the character code (like putting a space in a filename), but that is often problematic.

    – 0xSheepdog
    5 hours ago














3












3








3








I have been trying to:



cp file.csv file.$(date +%D).csv


But it fails because the filenames is: file.03/27/19.csv with the slash of separate directories.



And I have been trying again to:



cp file.csv file.$(printf "%q" $(date +%D)).csv


But it still fails.










share|improve this question
















I have been trying to:



cp file.csv file.$(date +%D).csv


But it fails because the filenames is: file.03/27/19.csv with the slash of separate directories.



And I have been trying again to:



cp file.csv file.$(printf "%q" $(date +%D)).csv


But it still fails.







shell filenames date escape-characters slash






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited 26 mins ago









Gilles

544k12811041621




544k12811041621










asked 5 hours ago









tres.14159tres.14159

2612




2612












  • You can not set a filename with slash characters: stackoverflow.com/questions/9847288/…

    – tres.14159
    5 hours ago











  • the problem is your use of the date format using the / character. You said it yourself, the shell is seeing them as directory markers. Try one of the many other options available from date. You might be able to get the / escaped so the filename uses the character code (like putting a space in a filename), but that is often problematic.

    – 0xSheepdog
    5 hours ago


















  • You can not set a filename with slash characters: stackoverflow.com/questions/9847288/…

    – tres.14159
    5 hours ago











  • the problem is your use of the date format using the / character. You said it yourself, the shell is seeing them as directory markers. Try one of the many other options available from date. You might be able to get the / escaped so the filename uses the character code (like putting a space in a filename), but that is often problematic.

    – 0xSheepdog
    5 hours ago

















You can not set a filename with slash characters: stackoverflow.com/questions/9847288/…

– tres.14159
5 hours ago





You can not set a filename with slash characters: stackoverflow.com/questions/9847288/…

– tres.14159
5 hours ago













the problem is your use of the date format using the / character. You said it yourself, the shell is seeing them as directory markers. Try one of the many other options available from date. You might be able to get the / escaped so the filename uses the character code (like putting a space in a filename), but that is often problematic.

– 0xSheepdog
5 hours ago






the problem is your use of the date format using the / character. You said it yourself, the shell is seeing them as directory markers. Try one of the many other options available from date. You might be able to get the / escaped so the filename uses the character code (like putting a space in a filename), but that is often problematic.

– 0xSheepdog
5 hours ago











1 Answer
1






active

oldest

votes


















10














You can't have / (byte 0x2F on ASCII-based systems) in a file name, period.



You can use characters that look like / like (fraction slash), so you could do:



 cp file.csv "file.$(date +%D | sed 's|/|⁄|g').csv"


But you may run into problems like the file name being rendered differently in locales using a different charset.



My advice would be to use the standard non-ambiguous (for most people outside the US, 03/12/18 would be interpreted as the 3rd of December 2018 for instance) YYYY-mm-dd format instead (which also helps wrt sorting):



 cp file.csv "file.$(date +%Y-%m-%d).csv"


Which with many date implementations you can shorten to:



 cp file.csv "file.$(date +%F).csv"





share|improve this answer
























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    1 Answer
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    1 Answer
    1






    active

    oldest

    votes









    active

    oldest

    votes






    active

    oldest

    votes









    10














    You can't have / (byte 0x2F on ASCII-based systems) in a file name, period.



    You can use characters that look like / like (fraction slash), so you could do:



     cp file.csv "file.$(date +%D | sed 's|/|⁄|g').csv"


    But you may run into problems like the file name being rendered differently in locales using a different charset.



    My advice would be to use the standard non-ambiguous (for most people outside the US, 03/12/18 would be interpreted as the 3rd of December 2018 for instance) YYYY-mm-dd format instead (which also helps wrt sorting):



     cp file.csv "file.$(date +%Y-%m-%d).csv"


    Which with many date implementations you can shorten to:



     cp file.csv "file.$(date +%F).csv"





    share|improve this answer





























      10














      You can't have / (byte 0x2F on ASCII-based systems) in a file name, period.



      You can use characters that look like / like (fraction slash), so you could do:



       cp file.csv "file.$(date +%D | sed 's|/|⁄|g').csv"


      But you may run into problems like the file name being rendered differently in locales using a different charset.



      My advice would be to use the standard non-ambiguous (for most people outside the US, 03/12/18 would be interpreted as the 3rd of December 2018 for instance) YYYY-mm-dd format instead (which also helps wrt sorting):



       cp file.csv "file.$(date +%Y-%m-%d).csv"


      Which with many date implementations you can shorten to:



       cp file.csv "file.$(date +%F).csv"





      share|improve this answer



























        10












        10








        10







        You can't have / (byte 0x2F on ASCII-based systems) in a file name, period.



        You can use characters that look like / like (fraction slash), so you could do:



         cp file.csv "file.$(date +%D | sed 's|/|⁄|g').csv"


        But you may run into problems like the file name being rendered differently in locales using a different charset.



        My advice would be to use the standard non-ambiguous (for most people outside the US, 03/12/18 would be interpreted as the 3rd of December 2018 for instance) YYYY-mm-dd format instead (which also helps wrt sorting):



         cp file.csv "file.$(date +%Y-%m-%d).csv"


        Which with many date implementations you can shorten to:



         cp file.csv "file.$(date +%F).csv"





        share|improve this answer















        You can't have / (byte 0x2F on ASCII-based systems) in a file name, period.



        You can use characters that look like / like (fraction slash), so you could do:



         cp file.csv "file.$(date +%D | sed 's|/|⁄|g').csv"


        But you may run into problems like the file name being rendered differently in locales using a different charset.



        My advice would be to use the standard non-ambiguous (for most people outside the US, 03/12/18 would be interpreted as the 3rd of December 2018 for instance) YYYY-mm-dd format instead (which also helps wrt sorting):



         cp file.csv "file.$(date +%Y-%m-%d).csv"


        Which with many date implementations you can shorten to:



         cp file.csv "file.$(date +%F).csv"






        share|improve this answer














        share|improve this answer



        share|improve this answer








        edited 4 hours ago

























        answered 5 hours ago









        Stéphane ChazelasStéphane Chazelas

        311k57588946




        311k57588946



























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