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Replace character with another only if repeated and not part of a word
Only match word outside a HTML statement with a regex“ReplaceWith” & - but only part of itRegExp regular expression find & replace whole words onlyJava regex - parts of wordsRegex match word groups and parts of previously matched word groupsWord replacement using regex if the target word is not a part of another wordreplace after “word” character by character in notepad ++?Why does `word (.(?!another-word))*?` match only a character?Replacing consecutive repeated characters in javareplacing part of a string but the part is very long
In Python3, the following code works to replace a string (two or more) of *
's with x
's.
import re
re.sub(r'*(?=*)|(?<=*)*', 'x', 'Replace this *** but not this *')
# 'Replace this xxx but not this *'
But what if I also want to exempt a string of *
's that are part of a "word" like the following? (I.e. the string is attached to one or more [a-zA-Z]
characters.)
text = "Don't replace foo*** or **bar, either."
# unmodified text expected
How do I do this? I can probably match the exempted cases as well and use a replacement function to deal with them, but is there a better way?
python regex python-3.x
add a comment |
In Python3, the following code works to replace a string (two or more) of *
's with x
's.
import re
re.sub(r'*(?=*)|(?<=*)*', 'x', 'Replace this *** but not this *')
# 'Replace this xxx but not this *'
But what if I also want to exempt a string of *
's that are part of a "word" like the following? (I.e. the string is attached to one or more [a-zA-Z]
characters.)
text = "Don't replace foo*** or **bar, either."
# unmodified text expected
How do I do this? I can probably match the exempted cases as well and use a replacement function to deal with them, but is there a better way?
python regex python-3.x
add a comment |
In Python3, the following code works to replace a string (two or more) of *
's with x
's.
import re
re.sub(r'*(?=*)|(?<=*)*', 'x', 'Replace this *** but not this *')
# 'Replace this xxx but not this *'
But what if I also want to exempt a string of *
's that are part of a "word" like the following? (I.e. the string is attached to one or more [a-zA-Z]
characters.)
text = "Don't replace foo*** or **bar, either."
# unmodified text expected
How do I do this? I can probably match the exempted cases as well and use a replacement function to deal with them, but is there a better way?
python regex python-3.x
In Python3, the following code works to replace a string (two or more) of *
's with x
's.
import re
re.sub(r'*(?=*)|(?<=*)*', 'x', 'Replace this *** but not this *')
# 'Replace this xxx but not this *'
But what if I also want to exempt a string of *
's that are part of a "word" like the following? (I.e. the string is attached to one or more [a-zA-Z]
characters.)
text = "Don't replace foo*** or **bar, either."
# unmodified text expected
How do I do this? I can probably match the exempted cases as well and use a replacement function to deal with them, but is there a better way?
python regex python-3.x
python regex python-3.x
edited 3 hours ago
0m3r
8,02292554
8,02292554
asked 4 hours ago
bongbangbongbang
607720
607720
add a comment |
add a comment |
2 Answers
2
active
oldest
votes
regex = r"s*2,[sn]"
This matches 2 or more *
chars, surrounded by whitespace (or ended with a newline)
Call it maybe like this?
regex = r"s*2,[sn]"
def replacer(match):
return 'x' * len(match.group())
re.sub(regex, replacer, your_string_here)
You gave me a good idea for the use of the replacer function, but your pattern, by including the spaces in the match, would seem to turnthis **** string
intothis******string
, which is not I want. It would also not replace**** this string
, which I do want to replace. That said, I now have a solution that works thanks to you. Thank you.
– bongbang
3 hours ago
add a comment |
This answer is inspired Danielle M.'s. This pattern below seems to give me what I want. The rest is the same as hers.
regex = r'(?<![a-zA-Z])*2,(?![a-zA-Z])'
add a comment |
Your Answer
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2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
regex = r"s*2,[sn]"
This matches 2 or more *
chars, surrounded by whitespace (or ended with a newline)
Call it maybe like this?
regex = r"s*2,[sn]"
def replacer(match):
return 'x' * len(match.group())
re.sub(regex, replacer, your_string_here)
You gave me a good idea for the use of the replacer function, but your pattern, by including the spaces in the match, would seem to turnthis **** string
intothis******string
, which is not I want. It would also not replace**** this string
, which I do want to replace. That said, I now have a solution that works thanks to you. Thank you.
– bongbang
3 hours ago
add a comment |
regex = r"s*2,[sn]"
This matches 2 or more *
chars, surrounded by whitespace (or ended with a newline)
Call it maybe like this?
regex = r"s*2,[sn]"
def replacer(match):
return 'x' * len(match.group())
re.sub(regex, replacer, your_string_here)
You gave me a good idea for the use of the replacer function, but your pattern, by including the spaces in the match, would seem to turnthis **** string
intothis******string
, which is not I want. It would also not replace**** this string
, which I do want to replace. That said, I now have a solution that works thanks to you. Thank you.
– bongbang
3 hours ago
add a comment |
regex = r"s*2,[sn]"
This matches 2 or more *
chars, surrounded by whitespace (or ended with a newline)
Call it maybe like this?
regex = r"s*2,[sn]"
def replacer(match):
return 'x' * len(match.group())
re.sub(regex, replacer, your_string_here)
regex = r"s*2,[sn]"
This matches 2 or more *
chars, surrounded by whitespace (or ended with a newline)
Call it maybe like this?
regex = r"s*2,[sn]"
def replacer(match):
return 'x' * len(match.group())
re.sub(regex, replacer, your_string_here)
answered 4 hours ago
Danielle M.Danielle M.
2,2051623
2,2051623
You gave me a good idea for the use of the replacer function, but your pattern, by including the spaces in the match, would seem to turnthis **** string
intothis******string
, which is not I want. It would also not replace**** this string
, which I do want to replace. That said, I now have a solution that works thanks to you. Thank you.
– bongbang
3 hours ago
add a comment |
You gave me a good idea for the use of the replacer function, but your pattern, by including the spaces in the match, would seem to turnthis **** string
intothis******string
, which is not I want. It would also not replace**** this string
, which I do want to replace. That said, I now have a solution that works thanks to you. Thank you.
– bongbang
3 hours ago
You gave me a good idea for the use of the replacer function, but your pattern, by including the spaces in the match, would seem to turn
this **** string
into this******string
, which is not I want. It would also not replace **** this string
, which I do want to replace. That said, I now have a solution that works thanks to you. Thank you.– bongbang
3 hours ago
You gave me a good idea for the use of the replacer function, but your pattern, by including the spaces in the match, would seem to turn
this **** string
into this******string
, which is not I want. It would also not replace **** this string
, which I do want to replace. That said, I now have a solution that works thanks to you. Thank you.– bongbang
3 hours ago
add a comment |
This answer is inspired Danielle M.'s. This pattern below seems to give me what I want. The rest is the same as hers.
regex = r'(?<![a-zA-Z])*2,(?![a-zA-Z])'
add a comment |
This answer is inspired Danielle M.'s. This pattern below seems to give me what I want. The rest is the same as hers.
regex = r'(?<![a-zA-Z])*2,(?![a-zA-Z])'
add a comment |
This answer is inspired Danielle M.'s. This pattern below seems to give me what I want. The rest is the same as hers.
regex = r'(?<![a-zA-Z])*2,(?![a-zA-Z])'
This answer is inspired Danielle M.'s. This pattern below seems to give me what I want. The rest is the same as hers.
regex = r'(?<![a-zA-Z])*2,(?![a-zA-Z])'
answered 3 hours ago
bongbangbongbang
607720
607720
add a comment |
add a comment |
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