How to enclose theorems and definition in rectangles?
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How to enclose theorems and definition in rectangles?
The following code
documentclassarticle
usepackageamsthm
usepackageamsmath
usepackagemathtools
usepackage[left=1.5in, right=1.5in, top=0.5in]geometry
newtheoremdefinitionDefinition
newtheoremtheoremTheorem
begindocument
titleExtra Credit
maketitle
begindefinition
If f is analytic at $z_0$, then the series
beginequation
f(z_0) + f'(z_0)(z-z_0) + fracf''(z_0)2!(z-z_0)^2 + cdots = sum_n=0^infty fracf^(n)(z_0)n!(z-z_0)^n
endequation
is called the Taylor series for f around $z_0$.
enddefinition
begintheorem
If f is analytic inside and on the simple closed positively oriented contour $Gamma$ and if $z_0$ is any point inside $Gamma$, then
beginequation
f^(n)(z_0) = fracn!2pi i int_Gamma fracf(zeta)(zeta - z_0)^n+1dzeta hspace1cm (n=1,2,3, cdots )
endequation
endtheorem
begintheorem
(Cauchy's Integral Formula) Let $Gamma$ be a simple closed positively oriented contour. If $f$ is analytic in some simply connected domain $D$ containing $Gamma$ and $z_0$ is any point inside $Gamma$, then
beginequation
f(z_0)= frac12pi i int_Gamma fracf(z)z-z_0 dz
endequation
endtheorem
noindent hrulefill
begintheorem
If f is analytic in the disk $|z-z_0|<R'$, then the Taylor series $(1)$ converges to $f(z)$ for all $z$ in this disk.
endtheorem
produces the following image
How can I enclose Definition 1, Theorem 1, and Theorem 2 in separate rectangles. And have these rectangles separated by a space?
spacing
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The following code
documentclassarticle
usepackageamsthm
usepackageamsmath
usepackagemathtools
usepackage[left=1.5in, right=1.5in, top=0.5in]geometry
newtheoremdefinitionDefinition
newtheoremtheoremTheorem
begindocument
titleExtra Credit
maketitle
begindefinition
If f is analytic at $z_0$, then the series
beginequation
f(z_0) + f'(z_0)(z-z_0) + fracf''(z_0)2!(z-z_0)^2 + cdots = sum_n=0^infty fracf^(n)(z_0)n!(z-z_0)^n
endequation
is called the Taylor series for f around $z_0$.
enddefinition
begintheorem
If f is analytic inside and on the simple closed positively oriented contour $Gamma$ and if $z_0$ is any point inside $Gamma$, then
beginequation
f^(n)(z_0) = fracn!2pi i int_Gamma fracf(zeta)(zeta - z_0)^n+1dzeta hspace1cm (n=1,2,3, cdots )
endequation
endtheorem
begintheorem
(Cauchy's Integral Formula) Let $Gamma$ be a simple closed positively oriented contour. If $f$ is analytic in some simply connected domain $D$ containing $Gamma$ and $z_0$ is any point inside $Gamma$, then
beginequation
f(z_0)= frac12pi i int_Gamma fracf(z)z-z_0 dz
endequation
endtheorem
noindent hrulefill
begintheorem
If f is analytic in the disk $|z-z_0|<R'$, then the Taylor series $(1)$ converges to $f(z)$ for all $z$ in this disk.
endtheorem
produces the following image
How can I enclose Definition 1, Theorem 1, and Theorem 2 in separate rectangles. And have these rectangles separated by a space?
spacing
New contributor
K.M is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
add a comment |
The following code
documentclassarticle
usepackageamsthm
usepackageamsmath
usepackagemathtools
usepackage[left=1.5in, right=1.5in, top=0.5in]geometry
newtheoremdefinitionDefinition
newtheoremtheoremTheorem
begindocument
titleExtra Credit
maketitle
begindefinition
If f is analytic at $z_0$, then the series
beginequation
f(z_0) + f'(z_0)(z-z_0) + fracf''(z_0)2!(z-z_0)^2 + cdots = sum_n=0^infty fracf^(n)(z_0)n!(z-z_0)^n
endequation
is called the Taylor series for f around $z_0$.
enddefinition
begintheorem
If f is analytic inside and on the simple closed positively oriented contour $Gamma$ and if $z_0$ is any point inside $Gamma$, then
beginequation
f^(n)(z_0) = fracn!2pi i int_Gamma fracf(zeta)(zeta - z_0)^n+1dzeta hspace1cm (n=1,2,3, cdots )
endequation
endtheorem
begintheorem
(Cauchy's Integral Formula) Let $Gamma$ be a simple closed positively oriented contour. If $f$ is analytic in some simply connected domain $D$ containing $Gamma$ and $z_0$ is any point inside $Gamma$, then
beginequation
f(z_0)= frac12pi i int_Gamma fracf(z)z-z_0 dz
endequation
endtheorem
noindent hrulefill
begintheorem
If f is analytic in the disk $|z-z_0|<R'$, then the Taylor series $(1)$ converges to $f(z)$ for all $z$ in this disk.
endtheorem
produces the following image
How can I enclose Definition 1, Theorem 1, and Theorem 2 in separate rectangles. And have these rectangles separated by a space?
spacing
New contributor
K.M is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
The following code
documentclassarticle
usepackageamsthm
usepackageamsmath
usepackagemathtools
usepackage[left=1.5in, right=1.5in, top=0.5in]geometry
newtheoremdefinitionDefinition
newtheoremtheoremTheorem
begindocument
titleExtra Credit
maketitle
begindefinition
If f is analytic at $z_0$, then the series
beginequation
f(z_0) + f'(z_0)(z-z_0) + fracf''(z_0)2!(z-z_0)^2 + cdots = sum_n=0^infty fracf^(n)(z_0)n!(z-z_0)^n
endequation
is called the Taylor series for f around $z_0$.
enddefinition
begintheorem
If f is analytic inside and on the simple closed positively oriented contour $Gamma$ and if $z_0$ is any point inside $Gamma$, then
beginequation
f^(n)(z_0) = fracn!2pi i int_Gamma fracf(zeta)(zeta - z_0)^n+1dzeta hspace1cm (n=1,2,3, cdots )
endequation
endtheorem
begintheorem
(Cauchy's Integral Formula) Let $Gamma$ be a simple closed positively oriented contour. If $f$ is analytic in some simply connected domain $D$ containing $Gamma$ and $z_0$ is any point inside $Gamma$, then
beginequation
f(z_0)= frac12pi i int_Gamma fracf(z)z-z_0 dz
endequation
endtheorem
noindent hrulefill
begintheorem
If f is analytic in the disk $|z-z_0|<R'$, then the Taylor series $(1)$ converges to $f(z)$ for all $z$ in this disk.
endtheorem
produces the following image
How can I enclose Definition 1, Theorem 1, and Theorem 2 in separate rectangles. And have these rectangles separated by a space?
spacing
spacing
New contributor
K.M is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
New contributor
K.M is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
New contributor
K.M is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
asked 1 min ago
K.MK.M
1235
1235
New contributor
K.M is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
New contributor
K.M is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
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K.M is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
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add a comment |
add a comment |
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