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What exact color does ozone gas have?
Does ozone (O₃) gas have a color?Does ozone (O₃) gas have a color?Are there any safety guidelines for mixing sulfate with chloride?Does O2 have a color in the gas phaseWhat color is solid methane?Describing the preparation of solutions and determining how many grams are needed to react with a substanceWhat does a molecules color have to do with its bond/orbital energies?Is lithium bicarbonate an aqueous solution of lithium carbonate?Unexpected behavior during preparation of copper hypophosphiteWhy does ozone have higher entropy than oxygen?Will UVC light/ozone affects color on fabrics?
$begingroup$
This answer to a now closed question says that ozone gas has a "slight blue" color. But there are lots of blue colors: sky blue, ultramarine, phthalo blue, many others — what is closer to the color of ozone?
This page shows photos of ozone solutions in water, like the one below, but this may not be representative of the color of the gas.
(source)
So, what exactly color does ozone gas have? Is it a single hue, or does it change depending on concentration/amount of ozone?
inorganic-chemistry color
$endgroup$
add a comment |
$begingroup$
This answer to a now closed question says that ozone gas has a "slight blue" color. But there are lots of blue colors: sky blue, ultramarine, phthalo blue, many others — what is closer to the color of ozone?
This page shows photos of ozone solutions in water, like the one below, but this may not be representative of the color of the gas.
(source)
So, what exactly color does ozone gas have? Is it a single hue, or does it change depending on concentration/amount of ozone?
inorganic-chemistry color
$endgroup$
add a comment |
$begingroup$
This answer to a now closed question says that ozone gas has a "slight blue" color. But there are lots of blue colors: sky blue, ultramarine, phthalo blue, many others — what is closer to the color of ozone?
This page shows photos of ozone solutions in water, like the one below, but this may not be representative of the color of the gas.
(source)
So, what exactly color does ozone gas have? Is it a single hue, or does it change depending on concentration/amount of ozone?
inorganic-chemistry color
$endgroup$
This answer to a now closed question says that ozone gas has a "slight blue" color. But there are lots of blue colors: sky blue, ultramarine, phthalo blue, many others — what is closer to the color of ozone?
This page shows photos of ozone solutions in water, like the one below, but this may not be representative of the color of the gas.
(source)
So, what exactly color does ozone gas have? Is it a single hue, or does it change depending on concentration/amount of ozone?
inorganic-chemistry color
inorganic-chemistry color
edited 15 mins ago
MackTuesday
22519
22519
asked 3 hours ago
RuslanRuslan
401113
401113
add a comment |
add a comment |
1 Answer
1
active
oldest
votes
$begingroup$
Due to Chappuis absorption, ozone does have a bluish color. To determine exactly what kind of blue it is, let's first look at the spectrum of absorption in the Chappuis band. The following plot was done using these data for 293K.
This is spectral cross-section of absorption. To determine color from this spectrum, we need to choose some parameters:
- Number density of ozone molecules,
- Thickness of ozone layer we're trying to visualize,
- Illuminant.
If we denote spectral radiance of our illuminant as $L(lambda)$, thickness of ozone layer as $d$, ozone molecule number density as $rho$, and absorption cross-section as $sigma(lambda)$, then we'll get the following expression for spectral radiance transmitted through the layer:
$$L_T(lambda)=L(lambda)expbig(-sigma(lambda)rho dbig).$$
The most sensible illuminant to choose for showing color of a material on the web is the CIE illuminant D65, whose color is the white point of the sRGB color space. Its spectrum can be found e.g. here.
We can find the color in XYZ space using CIE 1931 color matching functions (can be found e.g. here). The expression is
$$c_X=int_300^830L_T(lambda)bar x(lambda),mathrm dlambda,$$
and similarly for $Y$ and $Z$ coordinates. Then these can be transformed to sRGB using linear transformation matrix $mathrmXYZtomathrmsRGB$ given e.g. here and gamma-correcting to $gamma=1/2.2$ to yield final sRGB values.
Then, for ozone molecule number density $rho=10^25 fracmathrmmoleculemathrmm^3$ we'll get the following colors for different layer thicknesses:
For comparison, typical ozone column in the atmospheric ozone layer is about 300 Dobson units, which is equivalent to $2.687times10^20fracmathrmmoleculemathrm m^2$; with our $rho$ chosen above this corresponds to $d=8,mathrmmm$. So for daylight, ozone column has negligible effect on the sky color (unlike the evening — see the history of Chappuis absorption!).
As can be seen in the above plot, hue does change with increasing layer thickness. If we normalize the RGB values to see the hues of the thick layers (this would correspond to increasing illuminant power to compensate for absorption), we'll get the following hues:
Note that the violet hues in the above plot aren't accurate: they can't be accurately represented on sRGB monitors, so the plot only approximates them. They should be more saturated. Here's how the chromaticity changes from the white point to the most violet with increasing layer thickness (dashed triangle denotes the sRGB gamut):
$endgroup$
$begingroup$
Nice answer, but why did you ask the question? ;-)
$endgroup$
– Karl
2 hours ago
1
$begingroup$
@Karl Own Q-A duets are perfectly fine :)
$endgroup$
– andselisk
1 hour ago
2
$begingroup$
@Karl because the other question where I could have posted the answer is closed, and unlikely to be reopened given how long ago it happened. But since I think the question is still relevant (in the form "what color" instead of "does it have a color"), not easily (if at all) answered by googling, and interesting, I made this Q&A.
$endgroup$
– Ruslan
1 hour ago
$begingroup$
I just wanted to say that I've always loved sunsets, but until now I would never have guessed ozone was part of the reason; those deep blue-purples, contrasting with the orange-reds from Rayleigh scattering. You learn something new every day! Thanks so much for this contribution!
$endgroup$
– Nicolau Saker Neto
3 mins ago
add a comment |
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$begingroup$
Due to Chappuis absorption, ozone does have a bluish color. To determine exactly what kind of blue it is, let's first look at the spectrum of absorption in the Chappuis band. The following plot was done using these data for 293K.
This is spectral cross-section of absorption. To determine color from this spectrum, we need to choose some parameters:
- Number density of ozone molecules,
- Thickness of ozone layer we're trying to visualize,
- Illuminant.
If we denote spectral radiance of our illuminant as $L(lambda)$, thickness of ozone layer as $d$, ozone molecule number density as $rho$, and absorption cross-section as $sigma(lambda)$, then we'll get the following expression for spectral radiance transmitted through the layer:
$$L_T(lambda)=L(lambda)expbig(-sigma(lambda)rho dbig).$$
The most sensible illuminant to choose for showing color of a material on the web is the CIE illuminant D65, whose color is the white point of the sRGB color space. Its spectrum can be found e.g. here.
We can find the color in XYZ space using CIE 1931 color matching functions (can be found e.g. here). The expression is
$$c_X=int_300^830L_T(lambda)bar x(lambda),mathrm dlambda,$$
and similarly for $Y$ and $Z$ coordinates. Then these can be transformed to sRGB using linear transformation matrix $mathrmXYZtomathrmsRGB$ given e.g. here and gamma-correcting to $gamma=1/2.2$ to yield final sRGB values.
Then, for ozone molecule number density $rho=10^25 fracmathrmmoleculemathrmm^3$ we'll get the following colors for different layer thicknesses:
For comparison, typical ozone column in the atmospheric ozone layer is about 300 Dobson units, which is equivalent to $2.687times10^20fracmathrmmoleculemathrm m^2$; with our $rho$ chosen above this corresponds to $d=8,mathrmmm$. So for daylight, ozone column has negligible effect on the sky color (unlike the evening — see the history of Chappuis absorption!).
As can be seen in the above plot, hue does change with increasing layer thickness. If we normalize the RGB values to see the hues of the thick layers (this would correspond to increasing illuminant power to compensate for absorption), we'll get the following hues:
Note that the violet hues in the above plot aren't accurate: they can't be accurately represented on sRGB monitors, so the plot only approximates them. They should be more saturated. Here's how the chromaticity changes from the white point to the most violet with increasing layer thickness (dashed triangle denotes the sRGB gamut):
$endgroup$
$begingroup$
Nice answer, but why did you ask the question? ;-)
$endgroup$
– Karl
2 hours ago
1
$begingroup$
@Karl Own Q-A duets are perfectly fine :)
$endgroup$
– andselisk
1 hour ago
2
$begingroup$
@Karl because the other question where I could have posted the answer is closed, and unlikely to be reopened given how long ago it happened. But since I think the question is still relevant (in the form "what color" instead of "does it have a color"), not easily (if at all) answered by googling, and interesting, I made this Q&A.
$endgroup$
– Ruslan
1 hour ago
$begingroup$
I just wanted to say that I've always loved sunsets, but until now I would never have guessed ozone was part of the reason; those deep blue-purples, contrasting with the orange-reds from Rayleigh scattering. You learn something new every day! Thanks so much for this contribution!
$endgroup$
– Nicolau Saker Neto
3 mins ago
add a comment |
$begingroup$
Due to Chappuis absorption, ozone does have a bluish color. To determine exactly what kind of blue it is, let's first look at the spectrum of absorption in the Chappuis band. The following plot was done using these data for 293K.
This is spectral cross-section of absorption. To determine color from this spectrum, we need to choose some parameters:
- Number density of ozone molecules,
- Thickness of ozone layer we're trying to visualize,
- Illuminant.
If we denote spectral radiance of our illuminant as $L(lambda)$, thickness of ozone layer as $d$, ozone molecule number density as $rho$, and absorption cross-section as $sigma(lambda)$, then we'll get the following expression for spectral radiance transmitted through the layer:
$$L_T(lambda)=L(lambda)expbig(-sigma(lambda)rho dbig).$$
The most sensible illuminant to choose for showing color of a material on the web is the CIE illuminant D65, whose color is the white point of the sRGB color space. Its spectrum can be found e.g. here.
We can find the color in XYZ space using CIE 1931 color matching functions (can be found e.g. here). The expression is
$$c_X=int_300^830L_T(lambda)bar x(lambda),mathrm dlambda,$$
and similarly for $Y$ and $Z$ coordinates. Then these can be transformed to sRGB using linear transformation matrix $mathrmXYZtomathrmsRGB$ given e.g. here and gamma-correcting to $gamma=1/2.2$ to yield final sRGB values.
Then, for ozone molecule number density $rho=10^25 fracmathrmmoleculemathrmm^3$ we'll get the following colors for different layer thicknesses:
For comparison, typical ozone column in the atmospheric ozone layer is about 300 Dobson units, which is equivalent to $2.687times10^20fracmathrmmoleculemathrm m^2$; with our $rho$ chosen above this corresponds to $d=8,mathrmmm$. So for daylight, ozone column has negligible effect on the sky color (unlike the evening — see the history of Chappuis absorption!).
As can be seen in the above plot, hue does change with increasing layer thickness. If we normalize the RGB values to see the hues of the thick layers (this would correspond to increasing illuminant power to compensate for absorption), we'll get the following hues:
Note that the violet hues in the above plot aren't accurate: they can't be accurately represented on sRGB monitors, so the plot only approximates them. They should be more saturated. Here's how the chromaticity changes from the white point to the most violet with increasing layer thickness (dashed triangle denotes the sRGB gamut):
$endgroup$
$begingroup$
Nice answer, but why did you ask the question? ;-)
$endgroup$
– Karl
2 hours ago
1
$begingroup$
@Karl Own Q-A duets are perfectly fine :)
$endgroup$
– andselisk
1 hour ago
2
$begingroup$
@Karl because the other question where I could have posted the answer is closed, and unlikely to be reopened given how long ago it happened. But since I think the question is still relevant (in the form "what color" instead of "does it have a color"), not easily (if at all) answered by googling, and interesting, I made this Q&A.
$endgroup$
– Ruslan
1 hour ago
$begingroup$
I just wanted to say that I've always loved sunsets, but until now I would never have guessed ozone was part of the reason; those deep blue-purples, contrasting with the orange-reds from Rayleigh scattering. You learn something new every day! Thanks so much for this contribution!
$endgroup$
– Nicolau Saker Neto
3 mins ago
add a comment |
$begingroup$
Due to Chappuis absorption, ozone does have a bluish color. To determine exactly what kind of blue it is, let's first look at the spectrum of absorption in the Chappuis band. The following plot was done using these data for 293K.
This is spectral cross-section of absorption. To determine color from this spectrum, we need to choose some parameters:
- Number density of ozone molecules,
- Thickness of ozone layer we're trying to visualize,
- Illuminant.
If we denote spectral radiance of our illuminant as $L(lambda)$, thickness of ozone layer as $d$, ozone molecule number density as $rho$, and absorption cross-section as $sigma(lambda)$, then we'll get the following expression for spectral radiance transmitted through the layer:
$$L_T(lambda)=L(lambda)expbig(-sigma(lambda)rho dbig).$$
The most sensible illuminant to choose for showing color of a material on the web is the CIE illuminant D65, whose color is the white point of the sRGB color space. Its spectrum can be found e.g. here.
We can find the color in XYZ space using CIE 1931 color matching functions (can be found e.g. here). The expression is
$$c_X=int_300^830L_T(lambda)bar x(lambda),mathrm dlambda,$$
and similarly for $Y$ and $Z$ coordinates. Then these can be transformed to sRGB using linear transformation matrix $mathrmXYZtomathrmsRGB$ given e.g. here and gamma-correcting to $gamma=1/2.2$ to yield final sRGB values.
Then, for ozone molecule number density $rho=10^25 fracmathrmmoleculemathrmm^3$ we'll get the following colors for different layer thicknesses:
For comparison, typical ozone column in the atmospheric ozone layer is about 300 Dobson units, which is equivalent to $2.687times10^20fracmathrmmoleculemathrm m^2$; with our $rho$ chosen above this corresponds to $d=8,mathrmmm$. So for daylight, ozone column has negligible effect on the sky color (unlike the evening — see the history of Chappuis absorption!).
As can be seen in the above plot, hue does change with increasing layer thickness. If we normalize the RGB values to see the hues of the thick layers (this would correspond to increasing illuminant power to compensate for absorption), we'll get the following hues:
Note that the violet hues in the above plot aren't accurate: they can't be accurately represented on sRGB monitors, so the plot only approximates them. They should be more saturated. Here's how the chromaticity changes from the white point to the most violet with increasing layer thickness (dashed triangle denotes the sRGB gamut):
$endgroup$
Due to Chappuis absorption, ozone does have a bluish color. To determine exactly what kind of blue it is, let's first look at the spectrum of absorption in the Chappuis band. The following plot was done using these data for 293K.
This is spectral cross-section of absorption. To determine color from this spectrum, we need to choose some parameters:
- Number density of ozone molecules,
- Thickness of ozone layer we're trying to visualize,
- Illuminant.
If we denote spectral radiance of our illuminant as $L(lambda)$, thickness of ozone layer as $d$, ozone molecule number density as $rho$, and absorption cross-section as $sigma(lambda)$, then we'll get the following expression for spectral radiance transmitted through the layer:
$$L_T(lambda)=L(lambda)expbig(-sigma(lambda)rho dbig).$$
The most sensible illuminant to choose for showing color of a material on the web is the CIE illuminant D65, whose color is the white point of the sRGB color space. Its spectrum can be found e.g. here.
We can find the color in XYZ space using CIE 1931 color matching functions (can be found e.g. here). The expression is
$$c_X=int_300^830L_T(lambda)bar x(lambda),mathrm dlambda,$$
and similarly for $Y$ and $Z$ coordinates. Then these can be transformed to sRGB using linear transformation matrix $mathrmXYZtomathrmsRGB$ given e.g. here and gamma-correcting to $gamma=1/2.2$ to yield final sRGB values.
Then, for ozone molecule number density $rho=10^25 fracmathrmmoleculemathrmm^3$ we'll get the following colors for different layer thicknesses:
For comparison, typical ozone column in the atmospheric ozone layer is about 300 Dobson units, which is equivalent to $2.687times10^20fracmathrmmoleculemathrm m^2$; with our $rho$ chosen above this corresponds to $d=8,mathrmmm$. So for daylight, ozone column has negligible effect on the sky color (unlike the evening — see the history of Chappuis absorption!).
As can be seen in the above plot, hue does change with increasing layer thickness. If we normalize the RGB values to see the hues of the thick layers (this would correspond to increasing illuminant power to compensate for absorption), we'll get the following hues:
Note that the violet hues in the above plot aren't accurate: they can't be accurately represented on sRGB monitors, so the plot only approximates them. They should be more saturated. Here's how the chromaticity changes from the white point to the most violet with increasing layer thickness (dashed triangle denotes the sRGB gamut):
edited 1 hour ago
answered 3 hours ago
RuslanRuslan
401113
401113
$begingroup$
Nice answer, but why did you ask the question? ;-)
$endgroup$
– Karl
2 hours ago
1
$begingroup$
@Karl Own Q-A duets are perfectly fine :)
$endgroup$
– andselisk
1 hour ago
2
$begingroup$
@Karl because the other question where I could have posted the answer is closed, and unlikely to be reopened given how long ago it happened. But since I think the question is still relevant (in the form "what color" instead of "does it have a color"), not easily (if at all) answered by googling, and interesting, I made this Q&A.
$endgroup$
– Ruslan
1 hour ago
$begingroup$
I just wanted to say that I've always loved sunsets, but until now I would never have guessed ozone was part of the reason; those deep blue-purples, contrasting with the orange-reds from Rayleigh scattering. You learn something new every day! Thanks so much for this contribution!
$endgroup$
– Nicolau Saker Neto
3 mins ago
add a comment |
$begingroup$
Nice answer, but why did you ask the question? ;-)
$endgroup$
– Karl
2 hours ago
1
$begingroup$
@Karl Own Q-A duets are perfectly fine :)
$endgroup$
– andselisk
1 hour ago
2
$begingroup$
@Karl because the other question where I could have posted the answer is closed, and unlikely to be reopened given how long ago it happened. But since I think the question is still relevant (in the form "what color" instead of "does it have a color"), not easily (if at all) answered by googling, and interesting, I made this Q&A.
$endgroup$
– Ruslan
1 hour ago
$begingroup$
I just wanted to say that I've always loved sunsets, but until now I would never have guessed ozone was part of the reason; those deep blue-purples, contrasting with the orange-reds from Rayleigh scattering. You learn something new every day! Thanks so much for this contribution!
$endgroup$
– Nicolau Saker Neto
3 mins ago
$begingroup$
Nice answer, but why did you ask the question? ;-)
$endgroup$
– Karl
2 hours ago
$begingroup$
Nice answer, but why did you ask the question? ;-)
$endgroup$
– Karl
2 hours ago
1
1
$begingroup$
@Karl Own Q-A duets are perfectly fine :)
$endgroup$
– andselisk
1 hour ago
$begingroup$
@Karl Own Q-A duets are perfectly fine :)
$endgroup$
– andselisk
1 hour ago
2
2
$begingroup$
@Karl because the other question where I could have posted the answer is closed, and unlikely to be reopened given how long ago it happened. But since I think the question is still relevant (in the form "what color" instead of "does it have a color"), not easily (if at all) answered by googling, and interesting, I made this Q&A.
$endgroup$
– Ruslan
1 hour ago
$begingroup$
@Karl because the other question where I could have posted the answer is closed, and unlikely to be reopened given how long ago it happened. But since I think the question is still relevant (in the form "what color" instead of "does it have a color"), not easily (if at all) answered by googling, and interesting, I made this Q&A.
$endgroup$
– Ruslan
1 hour ago
$begingroup$
I just wanted to say that I've always loved sunsets, but until now I would never have guessed ozone was part of the reason; those deep blue-purples, contrasting with the orange-reds from Rayleigh scattering. You learn something new every day! Thanks so much for this contribution!
$endgroup$
– Nicolau Saker Neto
3 mins ago
$begingroup$
I just wanted to say that I've always loved sunsets, but until now I would never have guessed ozone was part of the reason; those deep blue-purples, contrasting with the orange-reds from Rayleigh scattering. You learn something new every day! Thanks so much for this contribution!
$endgroup$
– Nicolau Saker Neto
3 mins ago
add a comment |
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