Lowest total scrabble scoreCraft the longest Scrabble sentenceScrabble ImpossibilitiesHighest possible score my friend could earn in one Scrabble turn?What is the longest word that can be made out of all the scrabble tiles?What is the highest possible scrabble score for placing a single tile
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Lowest total scrabble score
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Lowest total scrabble score
Craft the longest Scrabble sentenceScrabble ImpossibilitiesHighest possible score my friend could earn in one Scrabble turn?What is the longest word that can be made out of all the scrabble tiles?What is the highest possible scrabble score for placing a single tile
$begingroup$
It's generally easier to get a low score in Scrabble than a high one. But is it easier to get a really low score?
Suppose you play a game of Scrabble by yourself in which you only make legal plays (that is, they'd withstand a challenge). You eventually play all of the tiles.
The order of play is important - if you make two words, you count them both. If you play on a double word score, the word that you formed is doubled (so you might want to start by playing a short word). Also remember that if you play all 7 tiles in your hand you get 50 points, so don't do that.
A lower bound on the score is 187. This is obviously not possible, as you're going to have to overlap words a fair bit. What is the lowest possible score you can get?
scrabble
asked 5 hours ago
SpitemasterSpitemaster
1514
New contributor
Spitemaster is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
$endgroup$
add a comment |
$begingroup$
It's generally easier to get a low score in Scrabble than a high one. But is it easier to get a really low score?
Suppose you play a game of Scrabble by yourself in which you only make legal plays (that is, they'd withstand a challenge). You eventually play all of the tiles.
The order of play is important - if you make two words, you count them both. If you play on a double word score, the word that you formed is doubled (so you might want to start by playing a short word). Also remember that if you play all 7 tiles in your hand you get 50 points, so don't do that.
A lower bound on the score is 187. This is obviously not possible, as you're going to have to overlap words a fair bit. What is the lowest possible score you can get?
scrabble
asked 5 hours ago
SpitemasterSpitemaster
1514
New contributor
Spitemaster is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
$endgroup$
$begingroup$
I added italics because I think that having to play all tiles is the most important constraint in the problem. Also, (to attempting solvers) I have an idea that it would be best to play very long words, so that overlapping is minimal. Also also, overlapping should probably be done with 1-point letters if possible (all while avoiding extra-point squares).
$endgroup$
– Brandon_J
5 hours ago
2
$begingroup$
Here's a link to a 1981 paper outlining the lowest possible scoring Scrabble games. No formal proof is given for their final answer, but it might be a good starting point.
$endgroup$
– DqwertyC
3 hours ago
add a comment |
$begingroup$
It's generally easier to get a low score in Scrabble than a high one. But is it easier to get a really low score?
Suppose you play a game of Scrabble by yourself in which you only make legal plays (that is, they'd withstand a challenge). You eventually play all of the tiles.
The order of play is important - if you make two words, you count them both. If you play on a double word score, the word that you formed is doubled (so you might want to start by playing a short word). Also remember that if you play all 7 tiles in your hand you get 50 points, so don't do that.
A lower bound on the score is 187. This is obviously not possible, as you're going to have to overlap words a fair bit. What is the lowest possible score you can get?
scrabble
asked 5 hours ago
SpitemasterSpitemaster
1514
New contributor
Spitemaster is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
$endgroup$
It's generally easier to get a low score in Scrabble than a high one. But is it easier to get a really low score?
Suppose you play a game of Scrabble by yourself in which you only make legal plays (that is, they'd withstand a challenge). You eventually play all of the tiles.
The order of play is important - if you make two words, you count them both. If you play on a double word score, the word that you formed is doubled (so you might want to start by playing a short word). Also remember that if you play all 7 tiles in your hand you get 50 points, so don't do that.
A lower bound on the score is 187. This is obviously not possible, as you're going to have to overlap words a fair bit. What is the lowest possible score you can get?
scrabble
scrabble
asked 5 hours ago
SpitemasterSpitemaster
1514
New contributor
Spitemaster is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
asked 5 hours ago
SpitemasterSpitemaster
1514
New contributor
Spitemaster is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
edited 4 hours ago
Spitemaster
asked 5 hours ago
SpitemasterSpitemaster
1514
New contributor
Spitemaster is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
asked 5 hours ago
SpitemasterSpitemaster
1514
asked 5 hours ago
SpitemasterSpitemaster
1514
1514
New contributor
Spitemaster is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
New contributor
Spitemaster is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
Spitemaster is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
$begingroup$
I added italics because I think that having to play all tiles is the most important constraint in the problem. Also, (to attempting solvers) I have an idea that it would be best to play very long words, so that overlapping is minimal. Also also, overlapping should probably be done with 1-point letters if possible (all while avoiding extra-point squares).
$endgroup$
– Brandon_J
5 hours ago
2
$begingroup$
Here's a link to a 1981 paper outlining the lowest possible scoring Scrabble games. No formal proof is given for their final answer, but it might be a good starting point.
$endgroup$
– DqwertyC
3 hours ago
add a comment |
$begingroup$
I added italics because I think that having to play all tiles is the most important constraint in the problem. Also, (to attempting solvers) I have an idea that it would be best to play very long words, so that overlapping is minimal. Also also, overlapping should probably be done with 1-point letters if possible (all while avoiding extra-point squares).
$endgroup$
– Brandon_J
5 hours ago
2
$begingroup$
Here's a link to a 1981 paper outlining the lowest possible scoring Scrabble games. No formal proof is given for their final answer, but it might be a good starting point.
$endgroup$
– DqwertyC
3 hours ago
$begingroup$
I added italics because I think that having to play all tiles is the most important constraint in the problem. Also, (to attempting solvers) I have an idea that it would be best to play very long words, so that overlapping is minimal. Also also, overlapping should probably be done with 1-point letters if possible (all while avoiding extra-point squares).
$endgroup$
– Brandon_J
5 hours ago
$begingroup$
I added italics because I think that having to play all tiles is the most important constraint in the problem. Also, (to attempting solvers) I have an idea that it would be best to play very long words, so that overlapping is minimal. Also also, overlapping should probably be done with 1-point letters if possible (all while avoiding extra-point squares).
$endgroup$
– Brandon_J
5 hours ago
2
2
$begingroup$
Here's a link to a 1981 paper outlining the lowest possible scoring Scrabble games. No formal proof is given for their final answer, but it might be a good starting point.
$endgroup$
– DqwertyC
3 hours ago
$begingroup$
Here's a link to a 1981 paper outlining the lowest possible scoring Scrabble games. No formal proof is given for their final answer, but it might be a good starting point.
$endgroup$
– DqwertyC
3 hours ago
add a comment |
2 Answers
2
active
oldest
votes
$begingroup$
I've managed a score of $225$. I'm sure a better score is possible, since there were a few places where I was not optimal.
It's impossible to avoid all the "special" squares on the board, so I chose only to hit a few of the Double Letter squares, which are no more penalizing than creating an extra join between words (i.e. it's probably more beneficial to cross a few Double Word squares and get a lot of longer words than it is to squeeze my way in between the "special" square using 3-letter words).
I started out using both blanks to negate the automatic Double Word that occurs on the starting square.
Here is the final board:
And here is the sequence of moves (they could go in many other orders without affecting the score):
(format is (Word score)(Cumulative score) Word (Uppercase indicates new tiles))
- (0)(0) IN (both blanks) (Double word)
- (1)(1) Rin (add the R)
- (15)(16) IMPrinTING (Double letters - I and N)
- (7)(23) iRING (Double letter - G)
- (23)(46) REACQUiring (Double letter - A)
- (15)(61) EXIgENT
- (8)(69) eBBS
- (8)(77) LOOsED (Double letter - O)
- (8)(85) tAKE
- (13)(98) SWeATY (Double letter - A)
- (8)(107) AUDiTOR
- (5)(112) IDEa
- (10)(122) MOOiNG (Double letter - O)
- (11)(133) AJAr
- (10)(143) FLaILS (Double letter - I)
- (16)(159) UNSaVVY
- (6)(165) ECRu
- (22)(187) WHEeZE (Double letter - E)
- (7)(194) TAUnTER
- (4)(198) tOIL
- (10)(208) POOlED (Double letter - O)
- (7)(215) rIFE
- (6)(223) HAe
- (2)(225) At
answered 3 hours ago
GentlePurpleRain♦GentlePurpleRain
16.9k569136
$endgroup$
$begingroup$
Whoops! Just noticed that there should be an extra 50 pts added, because I had one bingo. Will try to rework.
$endgroup$
– GentlePurpleRain♦
3 hours ago
$begingroup$
If you play Tournament rules, and (incorrectly) challenge each word, then you subtract 5 points each turn for 120 point discount.
$endgroup$
– Chris Cudmore
2 hours ago
1
$begingroup$
playing 'print (5)' instead of 'rin (1)' avoids the bingo and gives a total score of 229
$endgroup$
– Daniel Mathias
2 hours ago
1
$begingroup$
Out of interest, what's the Scrabble board editor you're using?
$endgroup$
– ZanyG
1 hour ago
$begingroup$
@ZanyG I just googled and found this one.
$endgroup$
– GentlePurpleRain♦
29 mins ago
|
show 1 more comment
$begingroup$
I started with the solution given in a paper found by DqwertyC in a comment. Unfortunately, it contains several errors, including invalid words, incorrect scoring, and the wrong tile distribution. Finding ways to resolve these errors gave me the following board.
The opening play is es, using both blanks. The next 3 plays of voicers, epigram, and thirties overlap only in blanks. Each of the subsequent $19$ plays forms one of the remaining $19$ visible words, overlapping in exactly one 1-point tile. The bonus squares used are $10$ 1-point tiles on double letter squares (at G3, I3, A4, I7, M7, D8, M9, A12, H12, and D15). Every play uses at most 6 tiles, so no bingos occur. This incurs a total penalty of $19+10=29$ on the total tile score of $187$, resulting in a final score of $187+29=216$.
answered 1 hour ago
noednenoedne
7,07712057
$endgroup$
add a comment |
Your Answer
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2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
$begingroup$
I've managed a score of $225$. I'm sure a better score is possible, since there were a few places where I was not optimal.
It's impossible to avoid all the "special" squares on the board, so I chose only to hit a few of the Double Letter squares, which are no more penalizing than creating an extra join between words (i.e. it's probably more beneficial to cross a few Double Word squares and get a lot of longer words than it is to squeeze my way in between the "special" square using 3-letter words).
I started out using both blanks to negate the automatic Double Word that occurs on the starting square.
Here is the final board:
And here is the sequence of moves (they could go in many other orders without affecting the score):
(format is (Word score)(Cumulative score) Word (Uppercase indicates new tiles))
- (0)(0) IN (both blanks) (Double word)
- (1)(1) Rin (add the R)
- (15)(16) IMPrinTING (Double letters - I and N)
- (7)(23) iRING (Double letter - G)
- (23)(46) REACQUiring (Double letter - A)
- (15)(61) EXIgENT
- (8)(69) eBBS
- (8)(77) LOOsED (Double letter - O)
- (8)(85) tAKE
- (13)(98) SWeATY (Double letter - A)
- (8)(107) AUDiTOR
- (5)(112) IDEa
- (10)(122) MOOiNG (Double letter - O)
- (11)(133) AJAr
- (10)(143) FLaILS (Double letter - I)
- (16)(159) UNSaVVY
- (6)(165) ECRu
- (22)(187) WHEeZE (Double letter - E)
- (7)(194) TAUnTER
- (4)(198) tOIL
- (10)(208) POOlED (Double letter - O)
- (7)(215) rIFE
- (6)(223) HAe
- (2)(225) At
answered 3 hours ago
GentlePurpleRain♦GentlePurpleRain
16.9k569136
$endgroup$
$begingroup$
Whoops! Just noticed that there should be an extra 50 pts added, because I had one bingo. Will try to rework.
$endgroup$
– GentlePurpleRain♦
3 hours ago
$begingroup$
If you play Tournament rules, and (incorrectly) challenge each word, then you subtract 5 points each turn for 120 point discount.
$endgroup$
– Chris Cudmore
2 hours ago
1
$begingroup$
playing 'print (5)' instead of 'rin (1)' avoids the bingo and gives a total score of 229
$endgroup$
– Daniel Mathias
2 hours ago
1
$begingroup$
Out of interest, what's the Scrabble board editor you're using?
$endgroup$
– ZanyG
1 hour ago
$begingroup$
@ZanyG I just googled and found this one.
$endgroup$
– GentlePurpleRain♦
29 mins ago
|
show 1 more comment
$begingroup$
I've managed a score of $225$. I'm sure a better score is possible, since there were a few places where I was not optimal.
It's impossible to avoid all the "special" squares on the board, so I chose only to hit a few of the Double Letter squares, which are no more penalizing than creating an extra join between words (i.e. it's probably more beneficial to cross a few Double Word squares and get a lot of longer words than it is to squeeze my way in between the "special" square using 3-letter words).
I started out using both blanks to negate the automatic Double Word that occurs on the starting square.
Here is the final board:
And here is the sequence of moves (they could go in many other orders without affecting the score):
(format is (Word score)(Cumulative score) Word (Uppercase indicates new tiles))
- (0)(0) IN (both blanks) (Double word)
- (1)(1) Rin (add the R)
- (15)(16) IMPrinTING (Double letters - I and N)
- (7)(23) iRING (Double letter - G)
- (23)(46) REACQUiring (Double letter - A)
- (15)(61) EXIgENT
- (8)(69) eBBS
- (8)(77) LOOsED (Double letter - O)
- (8)(85) tAKE
- (13)(98) SWeATY (Double letter - A)
- (8)(107) AUDiTOR
- (5)(112) IDEa
- (10)(122) MOOiNG (Double letter - O)
- (11)(133) AJAr
- (10)(143) FLaILS (Double letter - I)
- (16)(159) UNSaVVY
- (6)(165) ECRu
- (22)(187) WHEeZE (Double letter - E)
- (7)(194) TAUnTER
- (4)(198) tOIL
- (10)(208) POOlED (Double letter - O)
- (7)(215) rIFE
- (6)(223) HAe
- (2)(225) At
answered 3 hours ago
GentlePurpleRain♦GentlePurpleRain
16.9k569136
$endgroup$
$begingroup$
Whoops! Just noticed that there should be an extra 50 pts added, because I had one bingo. Will try to rework.
$endgroup$
– GentlePurpleRain♦
3 hours ago
$begingroup$
If you play Tournament rules, and (incorrectly) challenge each word, then you subtract 5 points each turn for 120 point discount.
$endgroup$
– Chris Cudmore
2 hours ago
1
$begingroup$
playing 'print (5)' instead of 'rin (1)' avoids the bingo and gives a total score of 229
$endgroup$
– Daniel Mathias
2 hours ago
1
$begingroup$
Out of interest, what's the Scrabble board editor you're using?
$endgroup$
– ZanyG
1 hour ago
$begingroup$
@ZanyG I just googled and found this one.
$endgroup$
– GentlePurpleRain♦
29 mins ago
|
show 1 more comment
$begingroup$
I've managed a score of $225$. I'm sure a better score is possible, since there were a few places where I was not optimal.
It's impossible to avoid all the "special" squares on the board, so I chose only to hit a few of the Double Letter squares, which are no more penalizing than creating an extra join between words (i.e. it's probably more beneficial to cross a few Double Word squares and get a lot of longer words than it is to squeeze my way in between the "special" square using 3-letter words).
I started out using both blanks to negate the automatic Double Word that occurs on the starting square.
Here is the final board:
And here is the sequence of moves (they could go in many other orders without affecting the score):
(format is (Word score)(Cumulative score) Word (Uppercase indicates new tiles))
- (0)(0) IN (both blanks) (Double word)
- (1)(1) Rin (add the R)
- (15)(16) IMPrinTING (Double letters - I and N)
- (7)(23) iRING (Double letter - G)
- (23)(46) REACQUiring (Double letter - A)
- (15)(61) EXIgENT
- (8)(69) eBBS
- (8)(77) LOOsED (Double letter - O)
- (8)(85) tAKE
- (13)(98) SWeATY (Double letter - A)
- (8)(107) AUDiTOR
- (5)(112) IDEa
- (10)(122) MOOiNG (Double letter - O)
- (11)(133) AJAr
- (10)(143) FLaILS (Double letter - I)
- (16)(159) UNSaVVY
- (6)(165) ECRu
- (22)(187) WHEeZE (Double letter - E)
- (7)(194) TAUnTER
- (4)(198) tOIL
- (10)(208) POOlED (Double letter - O)
- (7)(215) rIFE
- (6)(223) HAe
- (2)(225) At
answered 3 hours ago
GentlePurpleRain♦GentlePurpleRain
16.9k569136
$endgroup$
I've managed a score of $225$. I'm sure a better score is possible, since there were a few places where I was not optimal.
It's impossible to avoid all the "special" squares on the board, so I chose only to hit a few of the Double Letter squares, which are no more penalizing than creating an extra join between words (i.e. it's probably more beneficial to cross a few Double Word squares and get a lot of longer words than it is to squeeze my way in between the "special" square using 3-letter words).
I started out using both blanks to negate the automatic Double Word that occurs on the starting square.
Here is the final board:
And here is the sequence of moves (they could go in many other orders without affecting the score):
(format is (Word score)(Cumulative score) Word (Uppercase indicates new tiles))
- (0)(0) IN (both blanks) (Double word)
- (1)(1) Rin (add the R)
- (15)(16) IMPrinTING (Double letters - I and N)
- (7)(23) iRING (Double letter - G)
- (23)(46) REACQUiring (Double letter - A)
- (15)(61) EXIgENT
- (8)(69) eBBS
- (8)(77) LOOsED (Double letter - O)
- (8)(85) tAKE
- (13)(98) SWeATY (Double letter - A)
- (8)(107) AUDiTOR
- (5)(112) IDEa
- (10)(122) MOOiNG (Double letter - O)
- (11)(133) AJAr
- (10)(143) FLaILS (Double letter - I)
- (16)(159) UNSaVVY
- (6)(165) ECRu
- (22)(187) WHEeZE (Double letter - E)
- (7)(194) TAUnTER
- (4)(198) tOIL
- (10)(208) POOlED (Double letter - O)
- (7)(215) rIFE
- (6)(223) HAe
- (2)(225) At
answered 3 hours ago
GentlePurpleRain♦GentlePurpleRain
16.9k569136
answered 3 hours ago
GentlePurpleRain♦GentlePurpleRain
16.9k569136
answered 3 hours ago
GentlePurpleRain♦GentlePurpleRain
16.9k569136
answered 3 hours ago
GentlePurpleRain♦GentlePurpleRain
16.9k569136
16.9k569136
$begingroup$
Whoops! Just noticed that there should be an extra 50 pts added, because I had one bingo. Will try to rework.
$endgroup$
– GentlePurpleRain♦
3 hours ago
$begingroup$
If you play Tournament rules, and (incorrectly) challenge each word, then you subtract 5 points each turn for 120 point discount.
$endgroup$
– Chris Cudmore
2 hours ago
1
$begingroup$
playing 'print (5)' instead of 'rin (1)' avoids the bingo and gives a total score of 229
$endgroup$
– Daniel Mathias
2 hours ago
1
$begingroup$
Out of interest, what's the Scrabble board editor you're using?
$endgroup$
– ZanyG
1 hour ago
$begingroup$
@ZanyG I just googled and found this one.
$endgroup$
– GentlePurpleRain♦
29 mins ago
|
show 1 more comment
$begingroup$
Whoops! Just noticed that there should be an extra 50 pts added, because I had one bingo. Will try to rework.
$endgroup$
– GentlePurpleRain♦
3 hours ago
$begingroup$
If you play Tournament rules, and (incorrectly) challenge each word, then you subtract 5 points each turn for 120 point discount.
$endgroup$
– Chris Cudmore
2 hours ago
1
$begingroup$
playing 'print (5)' instead of 'rin (1)' avoids the bingo and gives a total score of 229
$endgroup$
– Daniel Mathias
2 hours ago
1
$begingroup$
Out of interest, what's the Scrabble board editor you're using?
$endgroup$
– ZanyG
1 hour ago
$begingroup$
@ZanyG I just googled and found this one.
$endgroup$
– GentlePurpleRain♦
29 mins ago
$begingroup$
Whoops! Just noticed that there should be an extra 50 pts added, because I had one bingo. Will try to rework.
$endgroup$
– GentlePurpleRain♦
3 hours ago
$begingroup$
Whoops! Just noticed that there should be an extra 50 pts added, because I had one bingo. Will try to rework.
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– GentlePurpleRain♦
3 hours ago
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If you play Tournament rules, and (incorrectly) challenge each word, then you subtract 5 points each turn for 120 point discount.
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– Chris Cudmore
2 hours ago
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If you play Tournament rules, and (incorrectly) challenge each word, then you subtract 5 points each turn for 120 point discount.
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– Chris Cudmore
2 hours ago
1
1
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playing 'print (5)' instead of 'rin (1)' avoids the bingo and gives a total score of 229
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– Daniel Mathias
2 hours ago
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playing 'print (5)' instead of 'rin (1)' avoids the bingo and gives a total score of 229
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– Daniel Mathias
2 hours ago
1
1
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Out of interest, what's the Scrabble board editor you're using?
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– ZanyG
1 hour ago
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Out of interest, what's the Scrabble board editor you're using?
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– ZanyG
1 hour ago
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@ZanyG I just googled and found this one.
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– GentlePurpleRain♦
29 mins ago
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@ZanyG I just googled and found this one.
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– GentlePurpleRain♦
29 mins ago
|
show 1 more comment
$begingroup$
I started with the solution given in a paper found by DqwertyC in a comment. Unfortunately, it contains several errors, including invalid words, incorrect scoring, and the wrong tile distribution. Finding ways to resolve these errors gave me the following board.
The opening play is es, using both blanks. The next 3 plays of voicers, epigram, and thirties overlap only in blanks. Each of the subsequent $19$ plays forms one of the remaining $19$ visible words, overlapping in exactly one 1-point tile. The bonus squares used are $10$ 1-point tiles on double letter squares (at G3, I3, A4, I7, M7, D8, M9, A12, H12, and D15). Every play uses at most 6 tiles, so no bingos occur. This incurs a total penalty of $19+10=29$ on the total tile score of $187$, resulting in a final score of $187+29=216$.
answered 1 hour ago
noednenoedne
7,07712057
$endgroup$
add a comment |
$begingroup$
I started with the solution given in a paper found by DqwertyC in a comment. Unfortunately, it contains several errors, including invalid words, incorrect scoring, and the wrong tile distribution. Finding ways to resolve these errors gave me the following board.
The opening play is es, using both blanks. The next 3 plays of voicers, epigram, and thirties overlap only in blanks. Each of the subsequent $19$ plays forms one of the remaining $19$ visible words, overlapping in exactly one 1-point tile. The bonus squares used are $10$ 1-point tiles on double letter squares (at G3, I3, A4, I7, M7, D8, M9, A12, H12, and D15). Every play uses at most 6 tiles, so no bingos occur. This incurs a total penalty of $19+10=29$ on the total tile score of $187$, resulting in a final score of $187+29=216$.
answered 1 hour ago
noednenoedne
7,07712057
$endgroup$
add a comment |
$begingroup$
I started with the solution given in a paper found by DqwertyC in a comment. Unfortunately, it contains several errors, including invalid words, incorrect scoring, and the wrong tile distribution. Finding ways to resolve these errors gave me the following board.
The opening play is es, using both blanks. The next 3 plays of voicers, epigram, and thirties overlap only in blanks. Each of the subsequent $19$ plays forms one of the remaining $19$ visible words, overlapping in exactly one 1-point tile. The bonus squares used are $10$ 1-point tiles on double letter squares (at G3, I3, A4, I7, M7, D8, M9, A12, H12, and D15). Every play uses at most 6 tiles, so no bingos occur. This incurs a total penalty of $19+10=29$ on the total tile score of $187$, resulting in a final score of $187+29=216$.
answered 1 hour ago
noednenoedne
7,07712057
$endgroup$
I started with the solution given in a paper found by DqwertyC in a comment. Unfortunately, it contains several errors, including invalid words, incorrect scoring, and the wrong tile distribution. Finding ways to resolve these errors gave me the following board.
The opening play is es, using both blanks. The next 3 plays of voicers, epigram, and thirties overlap only in blanks. Each of the subsequent $19$ plays forms one of the remaining $19$ visible words, overlapping in exactly one 1-point tile. The bonus squares used are $10$ 1-point tiles on double letter squares (at G3, I3, A4, I7, M7, D8, M9, A12, H12, and D15). Every play uses at most 6 tiles, so no bingos occur. This incurs a total penalty of $19+10=29$ on the total tile score of $187$, resulting in a final score of $187+29=216$.
answered 1 hour ago
noednenoedne
7,07712057
edited 1 hour ago
answered 1 hour ago
noednenoedne
7,07712057
answered 1 hour ago
noednenoedne
7,07712057
answered 1 hour ago
noednenoedne
7,07712057
7,07712057
add a comment |
add a comment |
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$begingroup$
I added italics because I think that having to play all tiles is the most important constraint in the problem. Also, (to attempting solvers) I have an idea that it would be best to play very long words, so that overlapping is minimal. Also also, overlapping should probably be done with 1-point letters if possible (all while avoiding extra-point squares).
$endgroup$
– Brandon_J
5 hours ago
2
$begingroup$
Here's a link to a 1981 paper outlining the lowest possible scoring Scrabble games. No formal proof is given for their final answer, but it might be a good starting point.
$endgroup$
– DqwertyC
3 hours ago