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What's the difference between mathrm and operatorname?

Difference between mathrm, operatorname and text?Define additional math operators to be typeset in romanWhich command should I use for textual subscripts in math mode?Further questions about mathrm and operatorname: spacing after colonHow to properly typeset E_mathrmk in beamerCorrectly left align a set of equationsHow to insert long subscripts involving characters?Error using equation*Incompatibility of lmodern and fourier?What's the difference between align and align*?Difference between textrm and mathrmWhat is the difference of mathop, operatorname and DeclareMathOperator?Difference between mathrm, operatorname and text?What is the difference between dfrac and frac?What's the difference between split and aligned?What's the difference between DeclareMathOperator and mathop?What is the difference between ifmmode and textormath?What's the difference between mspace and hspace in math mode?Further questions about mathrm and operatorname: spacing after colon

167

51

I apparently can't see the difference in a compilation (pdflatex) between mathrm and operatorname. So, as in the title the question is: is there a difference? Which one is preferable in what occasions?

math-mode amsmath math-operators

share|improve this question

edited Aug 25 '12 at 13:28

doncherry

35.3k23137209

asked Mar 18 '12 at 9:42

AndyAndy

945278

add a comment | 

167

51

I apparently can't see the difference in a compilation (pdflatex) between mathrm and operatorname. So, as in the title the question is: is there a difference? Which one is preferable in what occasions?

math-mode amsmath math-operators

share|improve this question

edited Aug 25 '12 at 13:28

doncherry

35.3k23137209

asked Mar 18 '12 at 9:42

AndyAndy

945278

add a comment | 

I apparently can't see the difference in a compilation (pdflatex) between mathrm and operatorname. So, as in the title the question is: is there a difference? Which one is preferable in what occasions?

math-mode amsmath math-operators

share|improve this question

edited Aug 25 '12 at 13:28

doncherry

35.3k23137209

asked Mar 18 '12 at 9:42

AndyAndy

945278

share|improve this question

edited Aug 25 '12 at 13:28

doncherry

35.3k23137209

asked Mar 18 '12 at 9:42

AndyAndy

945278

share|improve this question

edited Aug 25 '12 at 13:28

doncherry

35.3k23137209

asked Mar 18 '12 at 9:42

AndyAndy

945278

edited Aug 25 '12 at 13:28

doncherry

35.3k23137209

edited Aug 25 '12 at 13:28

doncherry

35.3k23137209

asked Mar 18 '12 at 9:42

AndyAndy

945278

asked Mar 18 '12 at 9:42

AndyAndy

945278

3 Answers
3

active

oldest

votes

194

There are many differences. The main one is in the fact that mathrmxyz behaves like an ordinary letter, while operatornamexyz behaves like function names such as sin. Here's an illustration

$sin x + sin(x+y) + asin z$

$mathrmsin x + mathrmsin(x+y) + amathrmsinz$

where it's clear that the second line is wrongly typeset. Even if your "operator" requires parentheses after it, it should be operatorname, as the third summand shows, where a thin space separates the coefficient from the operator.

Another subtle difference is in how some characters are interpreted in mathrm and in operatorname. Suppose you have an operator to be called "pre-norm", with a hyphen. Here's the example

$operatornamepre-norm(mathbfv)$

$mathrmpre-norm(mathbfv)$

and now it's clear what is to be used. Indeed operatorname (and the same holds for macros defined with DeclareMathOperator) treats in a special way punctuation symbols; mathrm, instead, treats them as math symbols.

share|improve this answer

answered Mar 18 '12 at 10:05

egregegreg

731k8919303252

• 
  
  
  

  
  1
  

  
  
  
  
  
  

  
  
  Can you please tell the full form of the rm in mathrm? Thank you!
  
  – Gaurang Tandon
  Feb 14 '18 at 5:12
  

  
  
  
  


• 
  
  
  

  
  2
  

  
  
  
  
  
  

  
  
  @GaurangTandon rm stands for “roman”, that conventionally denotes the upright type used in the document.
  
  – egreg
  Feb 14 '18 at 8:59
  

  
  
  
  

add a comment | 

34

mathrm:

It is like math mode (no spaces), but in upright mode. The font size isn't changed.

operatorname:

The argument is written in upright mode but with some additional
space before and behind.

The following example shows the differences:

documentclass[]article
usepackageamsmath
begindocument
[xoperatornamefooy]
[xmathrmfooy]
enddocument

share|improve this answer

answered Mar 18 '12 at 9:48

Marco DanielMarco Daniel

78.5k13223388

add a comment | 

9

In other LaTeX environments mathrmxyz is useful. In MathJax v 2.0

$ i \, mathrmsinh ; $

gave the equivalent output as $ i sinh x $. MathJax did not recognize operatorname.

share|improve this answer

edited Aug 26 '12 at 16:17

bodo

4,66211856

answered Aug 26 '12 at 16:02

cheltonchelton

9911

• 
  
  
  

  
  9
  

  
  
  
  
  
  

  
  
  operatorname is now supported with the ASMmath.js TeX extension.
  
  – ChrisR
  Dec 4 '13 at 16:10
  

  
  
  
  

add a comment | 

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194

There are many differences. The main one is in the fact that mathrmxyz behaves like an ordinary letter, while operatornamexyz behaves like function names such as sin. Here's an illustration

$sin x + sin(x+y) + asin z$

$mathrmsin x + mathrmsin(x+y) + amathrmsinz$

where it's clear that the second line is wrongly typeset. Even if your "operator" requires parentheses after it, it should be operatorname, as the third summand shows, where a thin space separates the coefficient from the operator.

Another subtle difference is in how some characters are interpreted in mathrm and in operatorname. Suppose you have an operator to be called "pre-norm", with a hyphen. Here's the example

$operatornamepre-norm(mathbfv)$

$mathrmpre-norm(mathbfv)$

and now it's clear what is to be used. Indeed operatorname (and the same holds for macros defined with DeclareMathOperator) treats in a special way punctuation symbols; mathrm, instead, treats them as math symbols.

share|improve this answer

answered Mar 18 '12 at 10:05

egregegreg

731k8919303252

• 
  
  
  

  
  1
  

  
  
  
  
  
  

  
  
  Can you please tell the full form of the rm in mathrm? Thank you!
  
  – Gaurang Tandon
  Feb 14 '18 at 5:12
  

  
  
  
  


• 
  
  
  

  
  2
  

  
  
  
  
  
  

  
  
  @GaurangTandon rm stands for “roman”, that conventionally denotes the upright type used in the document.
  
  – egreg
  Feb 14 '18 at 8:59
  

  
  
  
  

add a comment | 

194

There are many differences. The main one is in the fact that mathrmxyz behaves like an ordinary letter, while operatornamexyz behaves like function names such as sin. Here's an illustration

$sin x + sin(x+y) + asin z$

$mathrmsin x + mathrmsin(x+y) + amathrmsinz$

where it's clear that the second line is wrongly typeset. Even if your "operator" requires parentheses after it, it should be operatorname, as the third summand shows, where a thin space separates the coefficient from the operator.

Another subtle difference is in how some characters are interpreted in mathrm and in operatorname. Suppose you have an operator to be called "pre-norm", with a hyphen. Here's the example

$operatornamepre-norm(mathbfv)$

$mathrmpre-norm(mathbfv)$

and now it's clear what is to be used. Indeed operatorname (and the same holds for macros defined with DeclareMathOperator) treats in a special way punctuation symbols; mathrm, instead, treats them as math symbols.

share|improve this answer

answered Mar 18 '12 at 10:05

egregegreg

731k8919303252

• 
  
  
  

  
  1
  

  
  
  
  
  
  

  
  
  Can you please tell the full form of the rm in mathrm? Thank you!
  
  – Gaurang Tandon
  Feb 14 '18 at 5:12
  

  
  
  
  


• 
  
  
  

  
  2
  

  
  
  
  
  
  

  
  
  @GaurangTandon rm stands for “roman”, that conventionally denotes the upright type used in the document.
  
  – egreg
  Feb 14 '18 at 8:59
  

  
  
  
  

add a comment | 

There are many differences. The main one is in the fact that mathrmxyz behaves like an ordinary letter, while operatornamexyz behaves like function names such as sin. Here's an illustration

$sin x + sin(x+y) + asin z$

$mathrmsin x + mathrmsin(x+y) + amathrmsinz$

where it's clear that the second line is wrongly typeset. Even if your "operator" requires parentheses after it, it should be operatorname, as the third summand shows, where a thin space separates the coefficient from the operator.

Another subtle difference is in how some characters are interpreted in mathrm and in operatorname. Suppose you have an operator to be called "pre-norm", with a hyphen. Here's the example

$operatornamepre-norm(mathbfv)$

$mathrmpre-norm(mathbfv)$

and now it's clear what is to be used. Indeed operatorname (and the same holds for macros defined with DeclareMathOperator) treats in a special way punctuation symbols; mathrm, instead, treats them as math symbols.

share|improve this answer

answered Mar 18 '12 at 10:05

egregegreg

731k8919303252

$sin x + sin(x+y) + asin z$

$mathrmsin x + mathrmsin(x+y) + amathrmsinz$

$operatornamepre-norm(mathbfv)$

$mathrmpre-norm(mathbfv)$

share|improve this answer

answered Mar 18 '12 at 10:05

egregegreg

731k8919303252

answered Mar 18 '12 at 10:05

egregegreg

731k8919303252

answered Mar 18 '12 at 10:05

egregegreg

731k8919303252

34

mathrm:

It is like math mode (no spaces), but in upright mode. The font size isn't changed.

operatorname:

The argument is written in upright mode but with some additional
space before and behind.

The following example shows the differences:

documentclass[]article
usepackageamsmath
begindocument
[xoperatornamefooy]
[xmathrmfooy]
enddocument

share|improve this answer

answered Mar 18 '12 at 9:48

Marco DanielMarco Daniel

78.5k13223388

add a comment | 

34

mathrm:

It is like math mode (no spaces), but in upright mode. The font size isn't changed.

operatorname:

The argument is written in upright mode but with some additional
space before and behind.

The following example shows the differences:

documentclass[]article
usepackageamsmath
begindocument
[xoperatornamefooy]
[xmathrmfooy]
enddocument

share|improve this answer

answered Mar 18 '12 at 9:48

Marco DanielMarco Daniel

78.5k13223388

add a comment | 

mathrm:

It is like math mode (no spaces), but in upright mode. The font size isn't changed.

operatorname:

The argument is written in upright mode but with some additional
space before and behind.

The following example shows the differences:

documentclass[]article
usepackageamsmath
begindocument
[xoperatornamefooy]
[xmathrmfooy]
enddocument

share|improve this answer

answered Mar 18 '12 at 9:48

Marco DanielMarco Daniel

78.5k13223388

documentclass[]article
usepackageamsmath
begindocument
[xoperatornamefooy]
[xmathrmfooy]
enddocument

share|improve this answer

answered Mar 18 '12 at 9:48

Marco DanielMarco Daniel

78.5k13223388

answered Mar 18 '12 at 9:48

Marco DanielMarco Daniel

78.5k13223388

answered Mar 18 '12 at 9:48

Marco DanielMarco Daniel

78.5k13223388

9

In other LaTeX environments mathrmxyz is useful. In MathJax v 2.0

$ i \, mathrmsinh ; $

gave the equivalent output as $ i sinh x $. MathJax did not recognize operatorname.

share|improve this answer

edited Aug 26 '12 at 16:17

bodo

4,66211856

answered Aug 26 '12 at 16:02

cheltonchelton

9911

• 
  
  
  

  
  9
  

  
  
  
  
  
  

  
  
  operatorname is now supported with the ASMmath.js TeX extension.
  
  – ChrisR
  Dec 4 '13 at 16:10
  

  
  
  
  

add a comment | 

9

In other LaTeX environments mathrmxyz is useful. In MathJax v 2.0

$ i \, mathrmsinh ; $

gave the equivalent output as $ i sinh x $. MathJax did not recognize operatorname.

share|improve this answer

edited Aug 26 '12 at 16:17

bodo

4,66211856

answered Aug 26 '12 at 16:02

cheltonchelton

9911

• 
  
  
  

  
  9
  

  
  
  
  
  
  

  
  
  operatorname is now supported with the ASMmath.js TeX extension.
  
  – ChrisR
  Dec 4 '13 at 16:10
  

  
  
  
  

add a comment | 

In other LaTeX environments mathrmxyz is useful. In MathJax v 2.0

$ i \, mathrmsinh ; $

gave the equivalent output as $ i sinh x $. MathJax did not recognize operatorname.

share|improve this answer

edited Aug 26 '12 at 16:17

bodo

4,66211856

answered Aug 26 '12 at 16:02

cheltonchelton

9911

$ i \, mathrmsinh ; $

share|improve this answer

edited Aug 26 '12 at 16:17

bodo

4,66211856

answered Aug 26 '12 at 16:02

cheltonchelton

9911

edited Aug 26 '12 at 16:17

bodo

4,66211856

edited Aug 26 '12 at 16:17

bodo

4,66211856

answered Aug 26 '12 at 16:02

cheltonchelton

9911

answered Aug 26 '12 at 16:02

cheltonchelton

9911