Does higher Oxidation/ reduction potential translate to higher energy storage in battery? The Next CEO of Stack OverflowCan we create a galvanic cell with only half a cell connected to the ground?How can Nernst equation apply in this redox reaction?What are some factors that influence the voltage of voltaic/galvanic cells and why?ElectrochemistryWhat factors could lower the voltage of a galvanic cellElectrode Potential and Effect of Salt Bridge Ions on its ValueWhy does a complete discharge destroy a Li-Ion-Battery?Is flow battery cycle life really as high as the literature claims?water in redox reactionsRelationship between Yield and Applied Potentials
Easy to read palindrome checker
Expressing the idea of having a very busy time
Is there a way to save my career from absolute disaster?
How many extra stops do monopods offer for tele photographs?
Can I board the first leg of the flight without having final country's visa?
What is the difference between Statistical Mechanics and Quantum Mechanics
What was Carter Burke's job for "the company" in Aliens?
"Eavesdropping" vs "Listen in on"
Redefining symbol midway through a document
What does "shotgun unity" refer to here in this sentence?
What is the difference between "hamstring tendon" and "common hamstring tendon"?
AB diagonalizable then BA also diagonalizable
Can you teleport closer to a creature you are Frightened of?
Help! I cannot understand this game’s notations!
Is it ever safe to open a suspicious HTML file (e.g. email attachment)?
Which one is the true statement?
Help understanding this unsettling image of Titan, Epimetheus, and Saturn's rings?
Players Circumventing the limitations of Wish
How to avoid supervisors with prejudiced views?
How do I fit a non linear curve?
Does the Idaho Potato Commission associate potato skins with healthy eating?
What would be the main consequences for a country leaving the WTO?
Defamation due to breach of confidentiality
Is French Guiana a (hard) EU border?
Does higher Oxidation/ reduction potential translate to higher energy storage in battery?
The Next CEO of Stack OverflowCan we create a galvanic cell with only half a cell connected to the ground?How can Nernst equation apply in this redox reaction?What are some factors that influence the voltage of voltaic/galvanic cells and why?ElectrochemistryWhat factors could lower the voltage of a galvanic cellElectrode Potential and Effect of Salt Bridge Ions on its ValueWhy does a complete discharge destroy a Li-Ion-Battery?Is flow battery cycle life really as high as the literature claims?water in redox reactionsRelationship between Yield and Applied Potentials
$begingroup$
Some articles refer to the fact that Lithium is preferred metal of choice for batteries because their half cell voltage is high (slightly above 3V)
If that is the case why can't we use other metals like Mn which can have higher oxidation potential (Mn can have +7 oxidation state which translates to higher oxidation potential)?
electrochemistry
asked 7 hours ago
Karthick SKarthick S
61
New contributor
Karthick S is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
$endgroup$
add a comment |
$begingroup$
Some articles refer to the fact that Lithium is preferred metal of choice for batteries because their half cell voltage is high (slightly above 3V)
If that is the case why can't we use other metals like Mn which can have higher oxidation potential (Mn can have +7 oxidation state which translates to higher oxidation potential)?
electrochemistry
asked 7 hours ago
Karthick SKarthick S
61
New contributor
Karthick S is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
$endgroup$
1
$begingroup$
There is a difference in a high oxidation state and a large EMF. A number of factors are considered in making a battery, not just the EMF of the half cell. A battery can relatively easily have multiple cells to get a higher voltage.
$endgroup$
– MaxW
7 hours ago
add a comment |
$begingroup$
Some articles refer to the fact that Lithium is preferred metal of choice for batteries because their half cell voltage is high (slightly above 3V)
If that is the case why can't we use other metals like Mn which can have higher oxidation potential (Mn can have +7 oxidation state which translates to higher oxidation potential)?
electrochemistry
asked 7 hours ago
Karthick SKarthick S
61
New contributor
Karthick S is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
$endgroup$
Some articles refer to the fact that Lithium is preferred metal of choice for batteries because their half cell voltage is high (slightly above 3V)
If that is the case why can't we use other metals like Mn which can have higher oxidation potential (Mn can have +7 oxidation state which translates to higher oxidation potential)?
electrochemistry
electrochemistry
asked 7 hours ago
Karthick SKarthick S
61
New contributor
Karthick S is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
asked 7 hours ago
Karthick SKarthick S
61
New contributor
Karthick S is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
asked 7 hours ago
Karthick SKarthick S
61
New contributor
Karthick S is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
asked 7 hours ago
Karthick SKarthick S
61
asked 7 hours ago
Karthick SKarthick S
61
61
New contributor
Karthick S is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
New contributor
Karthick S is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
Karthick S is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
1
$begingroup$
There is a difference in a high oxidation state and a large EMF. A number of factors are considered in making a battery, not just the EMF of the half cell. A battery can relatively easily have multiple cells to get a higher voltage.
$endgroup$
– MaxW
7 hours ago
add a comment |
1
$begingroup$
There is a difference in a high oxidation state and a large EMF. A number of factors are considered in making a battery, not just the EMF of the half cell. A battery can relatively easily have multiple cells to get a higher voltage.
$endgroup$
– MaxW
7 hours ago
1
1
$begingroup$
There is a difference in a high oxidation state and a large EMF. A number of factors are considered in making a battery, not just the EMF of the half cell. A battery can relatively easily have multiple cells to get a higher voltage.
$endgroup$
– MaxW
7 hours ago
$begingroup$
There is a difference in a high oxidation state and a large EMF. A number of factors are considered in making a battery, not just the EMF of the half cell. A battery can relatively easily have multiple cells to get a higher voltage.
$endgroup$
– MaxW
7 hours ago
add a comment |
1 Answer
1
active
oldest
votes
$begingroup$
Energy storage depends on the electromotive potential (i.e. difference between species in the electromotive series) and on the number of electrons available.
Li, for example, has an oxidation potential of ~3.04 V relative to hydrogen, but Al has one of 1.66 V, so Li has the greater potential. On the other hand, Li has only one freely available outer electron, but Al has three, so Al stores more charge per mol, giving three times the capacity in coulombs on that basis. On the gripping hand, however, Li has a mass of ~7 amu, and Al is ~27 amu, so an aluminum cell carries around the dead weight of unused neutrons and inner electron/protons.
So, depending on the needs, Li batteries weigh relatively little and provide comparatively high potential, aluminum batteries would hold more charge at a bit lower voltage, and even Zn is useful, though deficient compared to those others in volts and coulombs (it also has a bunch of inert neutrons, but there is no charge for them), because it is relatively inexpensive.
answered 5 hours ago
DrMoishe PippikDrMoishe Pippik
14.5k1231
$endgroup$
add a comment |
StackExchange.ifUsing("editor", function ()
return StackExchange.using("mathjaxEditing", function ()
StackExchange.MarkdownEditor.creationCallbacks.add(function (editor, postfix)
StackExchange.mathjaxEditing.prepareWmdForMathJax(editor, postfix, [["$", "$"], ["\\(","\\)"]]);
);
);
, "mathjax-editing");
StackExchange.ready(function()
var channelOptions =
tags: "".split(" "),
id: "431"
;
initTagRenderer("".split(" "), "".split(" "), channelOptions);
StackExchange.using("externalEditor", function()
// Have to fire editor after snippets, if snippets enabled
if (StackExchange.settings.snippets.snippetsEnabled)
StackExchange.using("snippets", function()
createEditor();
);
else
createEditor();
);
function createEditor()
StackExchange.prepareEditor(
heartbeatType: 'answer',
autoActivateHeartbeat: false,
convertImagesToLinks: false,
noModals: true,
showLowRepImageUploadWarning: true,
reputationToPostImages: null,
bindNavPrevention: true,
postfix: "",
imageUploader:
brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
allowUrls: true
,
onDemand: true,
discardSelector: ".discard-answer"
,immediatelyShowMarkdownHelp:true
);
);
Karthick S is a new contributor. Be nice, and check out our Code of Conduct.
Sign up or log in
StackExchange.ready(function ()
StackExchange.helpers.onClickDraftSave('#login-link');
var $window = $(window),
onScroll = function(e)
var $elem = $('.new-login-left'),
docViewTop = $window.scrollTop(),
docViewBottom = docViewTop + $window.height(),
elemTop = $elem.offset().top,
elemBottom = elemTop + $elem.height();
if ((docViewTop elemBottom))
StackExchange.using('gps', function() StackExchange.gps.track('embedded_signup_form.view', location: 'question_page' ); );
$window.unbind('scroll', onScroll);
;
$window.on('scroll', onScroll);
);
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function ()
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fchemistry.stackexchange.com%2fquestions%2f111886%2fdoes-higher-oxidation-reduction-potential-translate-to-higher-energy-storage-in%23new-answer', 'question_page');
);
Post as a guest
Required, but never shown
1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
$begingroup$
Energy storage depends on the electromotive potential (i.e. difference between species in the electromotive series) and on the number of electrons available.
Li, for example, has an oxidation potential of ~3.04 V relative to hydrogen, but Al has one of 1.66 V, so Li has the greater potential. On the other hand, Li has only one freely available outer electron, but Al has three, so Al stores more charge per mol, giving three times the capacity in coulombs on that basis. On the gripping hand, however, Li has a mass of ~7 amu, and Al is ~27 amu, so an aluminum cell carries around the dead weight of unused neutrons and inner electron/protons.
So, depending on the needs, Li batteries weigh relatively little and provide comparatively high potential, aluminum batteries would hold more charge at a bit lower voltage, and even Zn is useful, though deficient compared to those others in volts and coulombs (it also has a bunch of inert neutrons, but there is no charge for them), because it is relatively inexpensive.
answered 5 hours ago
DrMoishe PippikDrMoishe Pippik
14.5k1231
$endgroup$
add a comment |
$begingroup$
Energy storage depends on the electromotive potential (i.e. difference between species in the electromotive series) and on the number of electrons available.
Li, for example, has an oxidation potential of ~3.04 V relative to hydrogen, but Al has one of 1.66 V, so Li has the greater potential. On the other hand, Li has only one freely available outer electron, but Al has three, so Al stores more charge per mol, giving three times the capacity in coulombs on that basis. On the gripping hand, however, Li has a mass of ~7 amu, and Al is ~27 amu, so an aluminum cell carries around the dead weight of unused neutrons and inner electron/protons.
So, depending on the needs, Li batteries weigh relatively little and provide comparatively high potential, aluminum batteries would hold more charge at a bit lower voltage, and even Zn is useful, though deficient compared to those others in volts and coulombs (it also has a bunch of inert neutrons, but there is no charge for them), because it is relatively inexpensive.
answered 5 hours ago
DrMoishe PippikDrMoishe Pippik
14.5k1231
$endgroup$
add a comment |
$begingroup$
Energy storage depends on the electromotive potential (i.e. difference between species in the electromotive series) and on the number of electrons available.
Li, for example, has an oxidation potential of ~3.04 V relative to hydrogen, but Al has one of 1.66 V, so Li has the greater potential. On the other hand, Li has only one freely available outer electron, but Al has three, so Al stores more charge per mol, giving three times the capacity in coulombs on that basis. On the gripping hand, however, Li has a mass of ~7 amu, and Al is ~27 amu, so an aluminum cell carries around the dead weight of unused neutrons and inner electron/protons.
So, depending on the needs, Li batteries weigh relatively little and provide comparatively high potential, aluminum batteries would hold more charge at a bit lower voltage, and even Zn is useful, though deficient compared to those others in volts and coulombs (it also has a bunch of inert neutrons, but there is no charge for them), because it is relatively inexpensive.
answered 5 hours ago
DrMoishe PippikDrMoishe Pippik
14.5k1231
$endgroup$
Energy storage depends on the electromotive potential (i.e. difference between species in the electromotive series) and on the number of electrons available.
Li, for example, has an oxidation potential of ~3.04 V relative to hydrogen, but Al has one of 1.66 V, so Li has the greater potential. On the other hand, Li has only one freely available outer electron, but Al has three, so Al stores more charge per mol, giving three times the capacity in coulombs on that basis. On the gripping hand, however, Li has a mass of ~7 amu, and Al is ~27 amu, so an aluminum cell carries around the dead weight of unused neutrons and inner electron/protons.
So, depending on the needs, Li batteries weigh relatively little and provide comparatively high potential, aluminum batteries would hold more charge at a bit lower voltage, and even Zn is useful, though deficient compared to those others in volts and coulombs (it also has a bunch of inert neutrons, but there is no charge for them), because it is relatively inexpensive.
answered 5 hours ago
DrMoishe PippikDrMoishe Pippik
14.5k1231
edited 21 mins ago
answered 5 hours ago
DrMoishe PippikDrMoishe Pippik
14.5k1231
answered 5 hours ago
DrMoishe PippikDrMoishe Pippik
14.5k1231
answered 5 hours ago
DrMoishe PippikDrMoishe Pippik
14.5k1231
14.5k1231
add a comment |
add a comment |
Karthick S is a new contributor. Be nice, and check out our Code of Conduct.
Karthick S is a new contributor. Be nice, and check out our Code of Conduct.
Karthick S is a new contributor. Be nice, and check out our Code of Conduct.
Karthick S is a new contributor. Be nice, and check out our Code of Conduct.
Thanks for contributing an answer to Chemistry Stack Exchange!
- Please be sure to answer the question. Provide details and share your research!
But avoid …
- Asking for help, clarification, or responding to other answers.
- Making statements based on opinion; back them up with references or personal experience.
Use MathJax to format equations. MathJax reference.
To learn more, see our tips on writing great answers.
Sign up or log in
StackExchange.ready(function ()
StackExchange.helpers.onClickDraftSave('#login-link');
var $window = $(window),
onScroll = function(e)
var $elem = $('.new-login-left'),
docViewTop = $window.scrollTop(),
docViewBottom = docViewTop + $window.height(),
elemTop = $elem.offset().top,
elemBottom = elemTop + $elem.height();
if ((docViewTop elemBottom))
StackExchange.using('gps', function() StackExchange.gps.track('embedded_signup_form.view', location: 'question_page' ); );
$window.unbind('scroll', onScroll);
;
$window.on('scroll', onScroll);
);
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function ()
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fchemistry.stackexchange.com%2fquestions%2f111886%2fdoes-higher-oxidation-reduction-potential-translate-to-higher-energy-storage-in%23new-answer', 'question_page');
);
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function ()
StackExchange.helpers.onClickDraftSave('#login-link');
var $window = $(window),
onScroll = function(e)
var $elem = $('.new-login-left'),
docViewTop = $window.scrollTop(),
docViewBottom = docViewTop + $window.height(),
elemTop = $elem.offset().top,
elemBottom = elemTop + $elem.height();
if ((docViewTop elemBottom))
StackExchange.using('gps', function() StackExchange.gps.track('embedded_signup_form.view', location: 'question_page' ); );
$window.unbind('scroll', onScroll);
;
$window.on('scroll', onScroll);
);
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function ()
StackExchange.helpers.onClickDraftSave('#login-link');
var $window = $(window),
onScroll = function(e)
var $elem = $('.new-login-left'),
docViewTop = $window.scrollTop(),
docViewBottom = docViewTop + $window.height(),
elemTop = $elem.offset().top,
elemBottom = elemTop + $elem.height();
if ((docViewTop elemBottom))
StackExchange.using('gps', function() StackExchange.gps.track('embedded_signup_form.view', location: 'question_page' ); );
$window.unbind('scroll', onScroll);
;
$window.on('scroll', onScroll);
);
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function ()
StackExchange.helpers.onClickDraftSave('#login-link');
var $window = $(window),
onScroll = function(e)
var $elem = $('.new-login-left'),
docViewTop = $window.scrollTop(),
docViewBottom = docViewTop + $window.height(),
elemTop = $elem.offset().top,
elemBottom = elemTop + $elem.height();
if ((docViewTop elemBottom))
StackExchange.using('gps', function() StackExchange.gps.track('embedded_signup_form.view', location: 'question_page' ); );
$window.unbind('scroll', onScroll);
;
$window.on('scroll', onScroll);
);
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
1
$begingroup$
There is a difference in a high oxidation state and a large EMF. A number of factors are considered in making a battery, not just the EMF of the half cell. A battery can relatively easily have multiple cells to get a higher voltage.
$endgroup$
– MaxW
7 hours ago