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Asymptote: 3d graph over a disc



The Next CEO of Stack OverflowSquiggly line in AsymptoteDrawing a surface over a nonrectangular domain in asymptotetransparency groups in asymptoteCropping 3D Graphs in AsymptoteAsymptote: have stuff outside the box3D Vector Fields in AsymptoteExport asymptote 3D arrowsUnderbrace in asymptoteproblems with labelpath asymptoteTikZ Arrowheads for Asymptote










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Is there a straightforward way to draw a 3D graph over a disc domain? Say
z=x^2-y^2 for x^2+y^2<1.



[I just started to use asymptote; this page explained me how to do it for a rectangular domain. I hope it is an easy question.]









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    Is there a straightforward way to draw a 3D graph over a disc domain? Say
    z=x^2-y^2 for x^2+y^2<1.



    [I just started to use asymptote; this page explained me how to do it for a rectangular domain. I hope it is an easy question.]









    share
























      0












      0








      0








      Is there a straightforward way to draw a 3D graph over a disc domain? Say
      z=x^2-y^2 for x^2+y^2<1.



      [I just started to use asymptote; this page explained me how to do it for a rectangular domain. I hope it is an easy question.]









      share














      Is there a straightforward way to draw a 3D graph over a disc domain? Say
      z=x^2-y^2 for x^2+y^2<1.



      [I just started to use asymptote; this page explained me how to do it for a rectangular domain. I hope it is an easy question.]







      graphs asymptote





      share












      share










      share



      share










      asked 2 mins ago









      Anton PetruninAnton Petrunin

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